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Papessa [141]
2 years ago
10

Please help me on this and thank you!

Mathematics
1 answer:
Lynna [10]2 years ago
7 0

Answer:

D

Step-by-step explanation:

We open it up, so 2/3x + -3 + -2 -1/3x, -3 + (-2) = -5.

2/3x - 1/3x - 5, 2/3x - 1/3x = 1/3x

Our final answer is 1/3x - 5

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Twice the difference of x and 7, is -23
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Step-by-step explanation:

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Tara is using matrix multiplication to find image points of a translation. She is translating the image 2 units left and 4 units
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Assuming that this is just on a 2-D coordinate plane, we must convert the expressions on to a 3-D plane since translation cannot be done on a 2-D plane. This is done by adding a dummy coordinate that does not change. Let us use "1" for this case.

Matrix:
| 0 0 -2 |(x) = (x - 2)
<span>| 0 0 4  |(y) = (y + 4)
</span><span>| 0 0 1  |(1) = 1</span>
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3 years ago
Rewrite 2/5 + 5/12 with a common denominator.
RoseWind [281]

Answer:60 is the common denominator

Step-by-step explanation:

4 0
3 years ago
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Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
What is the measure of E?
IceJOKER [234]
You can get E real quick
how? you know that D is 90 and f is given 66 and you know that D+E+F=180 so E=180-(90+66) which gives us 24
6 0
3 years ago
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