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docker41 [41]
3 years ago
12

Do you believe ethical truths are universal or relative? why?

SAT
1 answer:
Anna007 [38]3 years ago
5 0
While Ethical truths are thought by many to be universal (and some are) it actually fairly relative. This being because of different cultures and how specific treat or react to those “ethical truths”
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A point charge q1 = -4. 00 nc is at the point x = 0. 60 m, y = 0. 80 m , and a second point charge q2 = +6. 00 nc is at the poin
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The net electric field is the vector sum of the components of the electric

field produced by the two charges.

The values of the magnitude and direction of the net electric field at the origin (approximate values) are;

  • 131.6 N/C
  • 12.6 ° above the negative x–axis

<h3>How are the net electric field magnitude and direction calculated?</h3>

The possible questions based on a similar question posted online are;

(a) The net electric field at the origin.

The electric field due to charge q₁ is given as follows;

\vec E_{1x} = \mathbf{ \dfrac{1}{4 \cdot \pi \cdot \epsilon_0} \cdot \dfrac{q_1}{\vec{r}^2_2}}

Which gives;

\vec{E}_{1x} =\mathbf{ \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot cos\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) =-21.6 \, N/C

\vec{E}_{1y} = \mathbf{\dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot sin\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) = 28.8 \, N/C

Which gives;

\vec{E}_1 = \mathbf{21.6 \, N/C  \cdot \hat x +  28.8 \, N/C \hat y}

\vec{E}_{2x} = \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(6.00 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2} = 150 \, N/C

Therefore;

\vec  {E} = \left[ 21.6 \, N/C - 150 \, N/C \right] \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)

\vec  {E} = \mathbf{\left( -128.4 \, N/C  \right) \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)}

The magnitude of the net electric field is therefore;

E = \sqrt{(-128.4^2 + 28.8^2)} ≈ 131.6

  • The magnitude of the net electric field at the origin is E ≈<u> 131.6 N/C</u>

(b) The direction of the net electric field at the origin.

  • The \ direction \ is \ arctan \left(\dfrac{28.8}{-128.4} \right) \approx \underline{ 12.6^{\circ}} \ above \ the \ negative \ x-axis

Learn more about electric field strength here:

brainly.com/question/14743939

brainly.com/question/3591946

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Does (1, 0) make the equation y = 7x true?
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Well, from what I know, I believe that it does not. I don't see how it's possible, if y = 7, how does this relate to (0,1), I don't see how it's would be possible. My guess, it would impossible.

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Use the properties of logarithms to write the following expression as one logarithm. Logs logr + 8logr s − 3logr t mc001-1. Jpg
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In this exercise we have to use the properties of the logarithm to write it in one way, like this:

log(r+s)(rs)^8/(rt)^3

From these  recalling some properties of the logarithm, we find that:

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  • Logarithm of any base, whose logarithm is equal to 1, will always have the result equal to 0.
  • Two logarithms with the same base are equal when the logarithms are also equal.

given the equation as:

log(s)log(r)+8log(rs)-3log(rt)\\log(s+r)+8log(rs)-3log(rt)\\logg(r+s)(rs)^8/(rt)^3

See more about logarithm at brainly.com/question/10486788

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3 years ago
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