The net electric field is the vector sum of the components of the electric
field produced by the two charges.
The values of the magnitude and direction of the net electric field at the origin (approximate values) are;
- 12.6 ° above the negative x–axis
<h3>How are the net electric field magnitude and direction calculated?</h3>
The possible questions based on a similar question posted online are;
(a) The net electric field at the origin.
The electric field due to charge q₁ is given as follows;
Which gives;
Which gives;
Therefore;
![\vec {E} = \left[ 21.6 \, N/C - 150 \, N/C \right] \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)](https://tex.z-dn.net/?f=%5Cvec%20%20%7BE%7D%20%3D%20%5Cleft%5B%2021.6%20%5C%2C%20N%2FC%20-%20150%20%5C%2C%20N%2FC%20%5Cright%5D%20%5Cleft%28%20%5Chat%20x%20%5Cright%29%20%2B%20%5Cleft%2828.8%20%5C%2C%20N%2FC%20%5Cright%29%20%5Cleft%28%20%5Chat%20y%20%5Cright%29)
The magnitude of the net electric field is therefore;
E = 
≈ 131.6
- The magnitude of the net electric field at the origin is E ≈<u> 131.6 N/C</u>
(b) The direction of the net electric field at the origin.
Learn more about electric field strength here:
brainly.com/question/14743939
brainly.com/question/3591946
Answer:
the third one............
Explanation:
c) the third one
Well, from what I know, I believe that it does not. I don't see how it's possible, if y = 7, how does this relate to (0,1), I don't see how it's would be possible. My guess, it would impossible.
In this exercise we have to use the properties of the logarithm to write it in one way, like this:
From these recalling some properties of the logarithm, we find that:
- When the logarithm is equal to the base, the logarithm will always be equal to 1.
- Logarithm of any base, whose logarithm is equal to 1, will always have the result equal to 0.
- Two logarithms with the same base are equal when the logarithms are also equal.
given the equation as:
See more about logarithm at brainly.com/question/10486788
