All categories

3 years ago

Emily gad a decorative box that is shaped like a cube with a height of 5 inches. What’s the surface area of the box?

Mathematics

1 answer:

lina2011 [118]3 years ago

4 0

times the length by width and you will get your answer use a calculator that will be the answer

You might be interested in

Can someone please help me with this

zepelin [54]

Answer:

Step-by-step explanation:

6 0

2 years ago

The lines given by the equations y = 2x and y= 2x + 1 are

Elan Coil [88]

A. is the answer i’m pretty sure

7 0

2 years ago

12r-5 61° R A) 790 C) 140° B) 70° D) 970

Yanka [14]

Answer:

79 because x = 7 so 12 x7 - 5 =79

5 0

2 years ago

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

3 years ago

A spinner has 5 equally sized sections, 1 of which is gray and 4 of which are blue. The spinner is spun twice. What is the proba

nignag [31]

The first time is 4 over 5 and the second time is 1 over 5

4 0

3 years ago