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Oduvanchick [21]
3 years ago
8

Emily gad a decorative box that is shaped like a cube with a height of 5 inches. What’s the surface area of the box?

Mathematics
1 answer:
lina2011 [118]3 years ago
4 0

times the length by width and you will get your answer use a calculator that will be the answer

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Luke had $9. He had to spend 3/4 of it for a birthday gift. How much cash money did<br> he spend?
aivan3 [116]

Answer:

He spent $2.25.

Step-by-step explanation:

Multiply $9 by 3/4 and we get $6.75.

Now subtract $6.75 from $9.

We get $2.25

8 0
3 years ago
Read 2 more answers
Please help!! Asap!!
mamaluj [8]
We notice that for x = 2 , or x = 4, the value of y=0 (x intercept),

replace x by any of the latter value in y=a(x-3)² -1

===> 0= a( 2-1)² - 1====>a=1
7 0
3 years ago
Andres works at a job that pays him 12.50 an hour.Andres works 30 hours a week.How much does he make each month after 30% of cal
BlackZzzverrR [31]

Answer:

he makes $112.50

Step-by-step explanation:

first you have to find out how much he makes before tax is taken out. all you do is multiply 12.50 by 30, which gives you $375.00. then, you can either put in the calculator 30%375 or 0.3×375(both are the same thing) and you should get $112.50

8 0
3 years ago
1. In which quadrant does θ lie given that sinθ&gt;0 and cosθ&lt;0?
expeople1 [14]

Answer:

\theta is in quadrant II

Step-by-step explanation:

Given

\sin(\theta)  > 0 and \cos(\theta)  < 0

Required

Where is \theta

\sin(\theta)  > 0 and \cos(\theta)  < 0 imply that

\theta is in quadrant II

Because that is only quadrant where \sin(\theta)  > 0 and \cos(\theta)  < 0 exist.

4 0
3 years ago
What is (2,7) rotated 90% clockwise
ohaa [14]

Answer:

The required point is, (7, -2)

Step-by-step explanation:

The straight  line passing through (0,0) and (2,7) is,

y = (\frac {7 -0}{2-0}) \times x

⇒ y = 3.5x --------------(1)

Now, the straight line perpendicular to this line and passing through (0, 0) is

y = (\frac {-1}{3.5}) \times x

⇒ 7y + 2x = 0 -------------(2)

Let, (h,k) be the required point.

then, it is on the line 7y + 2x = 0

⇒7k + 2h = 0

⇒k = (\frac {-2}{7}) \times h ------------(3)

Again, distance from (0,0) of (h, k) is same as that of (2,7)

⇒ h^{2} + k^{2} = 4 + 49 = 53

⇒h^{2} \times (\frac {53}{49}) = 53 [putting the value of k from (3)]

⇒h^{2} = 49

⇒h = 7 [since, (h,k) is in 4th quadrant, so,h >0]

So, k = -2 [putting the value of h in (3)]

So, the required point is, (7, -2)

5 0
3 years ago
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