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HACTEHA [7]
3 years ago
5

A car drove 50 m/h for 3 hours, 65 mh for 30 minutes and 70 my for 1 hour. What was the cars average speed?

Mathematics
1 answer:
kykrilka [37]3 years ago
8 0
Speed is distance divided by time. First you have to find the total distance, so you would do (50*3)+(65*.5)+70(1). After you get that answer, you divide it by the time which would be 3 hours+.5 hours+1 hours. Just remember s=d/t.
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1. Which rule describes a translation that is 8 units to the right and 2 units up?
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There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red
madam [21]

Answer:

The probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

Step-by-step explanation:

Number of red marbles = 12

Number of green marbles = 8

Total number of marbles = 12+8 = 20

Probability of selecting red marble =\frac{12}{20}

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

Number of green marbles = 8

Probability of selecting green marble =\frac{8}{19}

So, the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag =\frac{12}{20} \times \frac{8}{19}=\frac{24}{95}

Hence the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

3 0
4 years ago
an electronics store sells large flat screen tvs for 1699 last month the store sold 8 of this tvs anout how much did the tvs sel
rusak2 [61]
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4 0
3 years ago
|x| + 4 > 7 plz help and hurry
Talja [164]

Answer:

The solution is (-\infty,-3)\cup(3,\infty).

Step-by-step explanation:

Given:

The inequality given is:

|x|+4>7

In order to simplify for 'x', we first isolate 'x' on one side.

Adding -4 on both sides, we get:

|x|+4-4>7-4\\\\|x|>3

Now, |x| is an absolute value function which is defined as:

|x|=\left \{ {{-x}\ \ x

Therefore, the given inequality can be rewritten as:

-x > 3\\x and x > 3

Therefore, the solution is (-\infty,-3)\cup(3,\infty).

4 0
3 years ago
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