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Pachacha [2.7K]

2 years ago

14

Katie stop erasing my questions im just trying to help idxiot

1 answer:

Anna007 [38]2 years ago

8 0

Answer:

HEY

Step-by-step explanation:

i think so u also dont know the que

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When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan

vitfil [10]

Answer:

$a = 6m/s^2$

Step-by-step explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

Required

Determine the acceleration when mass = 10kg, provided force is constant;

Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;

$a\ \alpha\ \frac{1}{m}$

Convert variation to equality

$a = \frac{F}{m}$ ; Where F is the constant of variation (Force)

Make F the subject of formula;

$F = ma$

When mass = 4kg; Acceleration = 15m/s²

$F = 4 * 15$

$F = 60N$

When mass = 10kg; Substitute 60 for Force

$F = ma$

$60 = 10 * a$

$60 = 10a$

Divide both sides by 10

$\frac{60}{10} = \frac{10a}{10}$

$a = 6m/s^2$

<em>Hence, the acceleration is </em> $a = 6m/s^2$ <em />

4 0

2 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

$Owl= 67.14ft$

7 0

2 years ago

What is the slope of the line that goes through -3,7 & -17,3

Natalka [10]

Point 1: (-3, 7)

Point 2: (-17, 3)

To find the slope, we need to use the slope formula which is as follows: m = (y2 - y1) / (x2 - x1). We will plug in each x and y coordinate from our points above, respectively.

m = (3 - 7) / (-17 - - 3)

m = (-4) / (-14)

m = 2/7

The slope of the line that goes through (-3, 7) and (-17, 3) is 2/7.

Hope this helps!! :)

7 0

2 years ago

Each employee receives a 5% raise find the mean median and mode of the data with the race how does this incurs affect the mean m

marshall27 [118]

Answer:

um

Step-by-step explanation:

um sorry bud cant help

7 0

2 years ago

A vehicle purchased for $

Nataly [62]

Answer:

$10,870

Step-by-step explanation:

we can multiply the initial value (27500) by (1-.06), or 0.94, raised to the 15th power

27500(.94)^15 = 10,870.52

6 0

2 years ago