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aksik [14]
3 years ago
10

HW#1 Square Root and Cube Root

Mathematics
1 answer:
scoray [572]3 years ago
3 0

Answer:

jhdondkod

ldllfk

ndlf

1?!dllf

hellojdk feon you tuve tío asmem dmdk jeux keju gilaa

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If one would dissolve 60g of sugar in 300g of water, what would the concentration of sugar in this syrup be?
Pie
Density of water = 1000 kg/m^3
1 m^3 = 1000 litres

Therefore,
1000 kg/1000 l => 1 kg/l => 1000 g/l

Then, 300 g of water = 300/1000 l = 0.3 l

The concentration of the syrup =  mass/amount of water = 60 g/0.3 l = 200 g/l 
3 0
4 years ago
Raul works at a movie theatre. The function f(x) represents the amount of money in dollars Raul earns per ticket, where x is the
sattari [20]

Answer:

Step-by-step explanation:

The function f(x) represents the amount of money in dollars Raul earns per ticket, where x is the number of tickets he sells. This is represented by the function,

f(x) = 3x2 + 16 - - - - - - -1

The function g(x) represents the number of tickets Raul sells per hour, where x is the number of hours he works. The function is represented by

g(x) = the square root of five times x cubed

g(x) = √(5x^3)

To find f(g(x)), we substitute g(x) into f(x).

f(g(x))= 3[√(5x^3)]^2 + 16

4 0
4 years ago
Read 2 more answers
How are weather balloons and weather satellites similar?
Ymorist [56]
The answer is A. Both collect weather data.

Answer B is false, Balloons generally deconstruct, Satellites do not as they are meant to orbit way past the stratosphere.
Answer C is false, Only satellites can go past the exosphere.
D. Neither of them have any sort of impact on the weather.


7 0
4 years ago
Read 2 more answers
At which values of x does the function F(x) have a vertical asymptote? <br> F(x)=1/x(x+6)(x-1)
Morgarella [4.7K]
Answer:
X=0
X=-6
X=1
Explanation: set the denominator equal to zero and solve for x
4 0
3 years ago
What are expressions for MN and LN? Hint Construct the altitude from M to LN.
Nikitich [7]

The question is missing the figure. So, it is in the atachment.

Answer: MN = x\sqrt{2}  LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

Step-by-step explanation: The first figure in the attachment is the figure of the question. The second figure is a way to respond this question by tracing the altitude from M to LN as suggested. When an altitude is drawn, it forms a 90° angle with the base, as shown in the drawing. To determine the other angle, you have to remember that all internal angles of a triangle sums up to 180°.

For the triangle <u>on the left</u> of the altitude:

45+90+angle=180

angle = 45

For the triangle <u>on the right</u>:

30+90+angle=180

angle = 60

With the angles, use the Law of Sines, which is relates sides and angles, as follows:

\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

For MN:

\frac{x}{sin(30)} = \frac{MN}{sin(45)}

MN = \frac{x.sen(45)}{sen(30)}

MN = x\sqrt{2}

For LN:

\frac{LN}{sen(105)} =\frac{x}{sin(30)}

LN = \frac{x.sin(105)}{sin(30)}

We can determine sin (105) as:

sin(105) = sin(45+60)

sin(105) = sin(45)cos(60) + cos(45)sin(60)

sin(105) = \frac{\sqrt{2} }{2}.\frac{1}{2} + \frac{\sqrt{2} }{2}.\frac{\sqrt{3} }{2}

sin(105) = \frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}

LN = \frac{x.sin(105)}{sin(30)}

LN = x.(\frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}  ) .2

LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

The expressions for:

MN = x\sqrt{2}

LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

6 0
3 years ago
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