What is the amplitude of the sinusoid given by y=-3 sin (5x) ?
2 answers:
Answer:
The amplitude of the sinusoid given by y=-3sin(5x) is -3.
Step-by-step explanation:
The equation of the sinusoid can be written in the general form as:
asin(bx-c)+d,
Comparing the given equation that is y=-3sin(5x) with the above equation, we get a=-3, b=5 and c=0 and d=0.
therefore,the amplitude of the sinusoid given by y=-3sin(5x) is -3.
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