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AURORKA [14]
2 years ago
13

A fireperson needs to use a ladder of 25 feet in length to rescue a cat that has become

Mathematics
1 answer:
svp [43]2 years ago
5 0

Answer:

A, because the cat is only 15 feet in the air and the TREE is 50 feet

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Marshall took $36.75 to a fair. Each ticket into the fair costs x dollars. Marshall bought 3 tickets. Which
slamgirl [31]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
Solve for x. 4(2-x)+13=2x+3
gregori [183]

Answer:

x = 3

Step-by-step explanation:

4(2-x)+13=2x+3

distribute the 4.

8 - 4x + 13 = 2x + 3

combine like terms.

21 - 4x = 2x + 3

18 = 6x

divide by 6.

x = 3

check.

4(2 - 3) + 13 = 2(3) + 3

4(-1) + 13 = 6 + 3

-4 + 13 = 9

9 = 9

correct!

4 0
3 years ago
The American Water Works Association reports that the per capita water use in a single-family home is 74 gallons per day. Legacy
Lunna [17]

Answer:

Reject H0 since test statistic <-2.492

Step-by-step explanation:

Given that the American Water Works Association reports that the per capita water use in a single-family home is 74 gallons per day.

n = 25

x bar = 69

s= 8.3

std error = s/sqrt n = \frac{8.3}{5} \\=1.66

H0:\bar x = 74

Ha: \bar x

(Left tailed test at 5% significance level)

a) Reject H0 if t\leq-2.492

b) Test statistic = mean difference/std error

= \frac{69-74}{1.66} \\=-3.012\\

=-3.01

df =24

c) Reject H0

6 0
3 years ago
1+1=?<br> Sana Naman yung tamang sagot lang
Naily [24]

Answer:

2

Step-by-step explanation:

1+ 1 = 2

Hope this helps

plz mark as brainliest!!!!!!!

5 0
3 years ago
Read 2 more answers
What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*
pickupchik [31]
<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation x^4-41x^2=-400.

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

x^4-41x^2+400=-400+400.

x^4-41x^2+400=0.

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

x^4-25x^2-16x^2+400=0

Making it into two groups, we get

(x^4-25x^2)+(-16x^2+400)=0

Factoring out GCF of each group, we get

x^2(x^2-25)-16(x^2-25)=0

(x^2-25)(x^2-16) =0

Factoring out  (x^2-25) and (x^2-16) separately by difference of the squares identity a^2-b^2=(a-b)(a+b), we get

(x^2-25) = x^2-5^2= (x-5)(x+5) and

x^2-16 = x^2-4^2 =(x-4)(x+4).

Therefore,

(x-5)(x+5)(x-4)(x+4) =0

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>
6 0
3 years ago
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