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AURORKA [14]
2 years ago
13

A fireperson needs to use a ladder of 25 feet in length to rescue a cat that has become

Mathematics
1 answer:
svp [43]2 years ago
5 0

Answer:

A, because the cat is only 15 feet in the air and the TREE is 50 feet

You might be interested in
Which of the following proportions is false? 10/25 = 40/100 24/30 = 20/25 18/48 = 20/50 25/45 = 75/135
Liono4ka [1.6K]

Answer:

18/48=20/50 is wrong

Step-by-step explanation:

Because 18/48=37.5% and 20/50=40%

Hope it helps

3 0
2 years ago
Explain what 78.5% would look like on a 100% block. Then write it as a decimal.
Gennadij [26K]
78.5/100 as a decimal is just 0.78.5 and as a percent it is 78.5 %

5 0
3 years ago
Read 2 more answers
15.5 decimeters but in meters
ivanzaharov [21]

Answer:

There are 10 decimeters in one meter so the answer is 15.5 / 10 = 1.55 meters.

3 0
3 years ago
Read 2 more answers
Another question for math. ill give mad points, the question is in attachment
yulyashka [42]
For this case we have the following points:
 y = (- 2, 5)
 z = (1, 3)
 Therefore, the vector yz is given by:
 yz = z - y = (1, 3) - (-2, 5)
 yz = ((1 - (- 2)), (3-5))
 yz = ((1 + 2), -2)
 yz = (3, -2)
 Then, the magnitude is given by:
 lyzl = root ((3) ^ 2 + (-2) ^ 2)
 lyzl = root (9 + 4)
 lyzl = root (13)
 Answer:
 
yz = (3, -2)
 lyzl = root (13)
 option A
5 0
3 years ago
What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

8 0
2 years ago
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