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tresset_1 [31]
3 years ago
14

I don't know how to do this can someone please help me?

Mathematics
2 answers:
tatuchka [14]3 years ago
7 0

Answer:

  1. The area of a circle is

Step-by-step explanation:

The area of a circle is got by

Given that radius is 49,

Area will be π which equals 3.14 49 multiplied by square radius.

That's calculated as 3.14×49×49 =7,539.14

Answer rounded to the nearest hundreds equals 7500.

End of the answer.

Dear learner I can further assist with your homework should need be and I am available on plus one six one nine five five eight two one four zero.

kotykmax [81]3 years ago
5 0

Given - diameter = 98 cm

So radius = 98/2

=> radius = 49 cm

Area of circle = πr^2

=> Area of circle = 22/7 * 49 * 49

=> Area of circle = 7,546 cm^2

PLEASE MARK AS BRAINLIEST

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Step-by-step explanation:

5 0
3 years ago
Two sets of equatic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2: x
kherson [118]

Answer:  The correct line is

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Step-by-step explanation:  We are given the following two sets of quadratic expressions in various forms:

\textup{Line 1: }x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25,\\\\\textup{Line 2 :}x^2+5x+6=(x+2)(x+3)=(x+2.5)^2+6.25.

We are to select one of the lines from above that represent three equivalent expressions.

We can see that there are three different forms of a quadratic expression in each of the lines:

First one is the simplified form, second is the factorised form and third one is the vertex form.

So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.

We have

\textup{Line 1: }\\\\x^2+3x+2\\\\=x^2+2x+x+2\\\\=x(x+2)+1(x+2)\\\\=(x+1)(x+2),

and

x^2+3x+2\\\\=x^2+2\times x\times 1.5+(1.5)^2-(1.5)^2+2\\\\=(x+1.5)^2-2.25+2\\\\=(x+1.5)^2-0.25.

So,

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Thus, Line 1 contains three equivalent expressions.

Now,

\textup{Line 2: }\\\\x^2+5x+6\\\\=x^2+3x+2x+6\\\\=x(x+3)+2(x+3)\\\\=(x+2)(x+3),

and

x^2+5x+6\\\\=x^2+2\times x\times 2.5+(2.5)^2-(2.5)^2+6\\\\=(x+2.5)^2-6.25+6\\\\=(x+2.5)^2-0.25\neq (x+2.5)^2+6.25.

So,

\textup{Line 2 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2+6.25.

Thus, Line 2 does not contain three equivalent expressions.

Hence, Line 1 is correct.

7 0
4 years ago
Circles A, B, and C overlap. x is in the overlap of circles A and B. Which of the following are true about x? Check all that app
Bond [772]

9514 1404 393

Answer:

  b, c, d, e, f

Step-by-step explanation:

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x ∈ A ⋃ B . . . true

x ∈ A ⋃ C . . . true

x ∈ A ⋂ B . . . true (x is in the overlap)

4 0
3 years ago
Read 2 more answers
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