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makkiz [27]
3 years ago
11

Given circle Q with a measure of SR=120° and a radius of 9 feet, as shown below.

Mathematics
1 answer:
Pie3 years ago
6 0

Answer:

18.85 feet

Step-by-step explanation:

Determine the arc length of SR

Arc length = θ/360 × 2πr

r = 9 feet

θ =120°

Arc length = 120/360 × 2 × π × 9

= 18.849555922 feet

Approximately = 18.85 feet

Therefore, the arc length of SR = 18.85 feet

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and

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\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

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m^2-n^2=4\sqrt{mn}

as required.

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3 years ago
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