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KengaRu [80]
3 years ago
13

Marco ate pizza for dinner last night he had 7/12 of the pizza left over. His brothers woke up this morning and ate 2/3 of what

was left of the pizza. How much of the whole pizza did his brothers eat?
Mathematics
1 answer:
Ahat [919]3 years ago
7 0
•) Change both denominators to twelve since 12 goes into 3 4 times. Now, add 7+2. The answer is 9. 9/12 can be simplified. Divide 9/3 and 12/3. Your answer is 3/4.
You might be interested in
Are 30:12 and 40:16 equivelant if noy tell why
mihalych1998 [28]
They are equivalent

30:12 => 5:2
40:16 => 5:2

hope this helsp
4 0
3 years ago
A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
2 years ago
PLEASE HELP IMMEDIATELY
grandymaker [24]

Answer:

a)   C(d) = 37.95 + 0.62d

b)  C(74) = 37.95 + 0.62(74)

83.8 dollars

c) 8181 miles

Step-by-step explanation:

The company charges a fee of 37.95 just for the rent and then 0.62 dollars per mile.

So if one person travels one mile they will pay:

37.95 + 0.62

Two miles: 37.95 + 0.62 (2)

Three miles: 37.95 + 0.62 (3)

d miles: 37.95 + 0.62(d)

Thus, the function C(d) that gives the total cost of renting the truck for one day if you drive d miles would be C(d) = 37.95 + 0.62d

Now, if we drive 74 miles, the function that gives us the cost would be:

C(74) = 37.95 + 0.62(74) = 37.95 + 45.88 = 83.83 = 83.8 dollars

Now, if we have 5110 dollars on our budget, we would have to substitute this in our function to know how many miles we can drive with that amount:

C(d)= 37.95+0.62d=5110\\37.95+0.62d=5110\\0.62d=5110-37.95\\0.62d=5072.05\\d=5072.05/ 0.62 \\d=8180.7

Thus, we could drive 8181 miles

3 0
3 years ago
Quadrilateral ABCD ABCD is similar to quadrilateral EFGH EFGH. The lengths of the three longest sides in quadrilateral ABCD ABCD
Kay [80]
Sketch the two quadrilaterals and label them as shown in the figure below.

Let x =  length of the 4th side of ABCD.

Because ABCD ~ EFGH, therefore
x/5 = 14/6

That is,
x = (5/6)*14 = 11.67 ft

Answer: D. 11.7 ft

5 0
3 years ago
Statistics Practice Q8
Ghella [55]
The answer is B, at first the sum is 621 and then you divide by 7 to get your median (88), after you add the two #s of 86 and 87 to 621 and divide by 9. Resulting in the median being 88
6 0
3 years ago
Read 2 more answers
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