B., the mass of the nucleus of the atom.
Both the protons and the neutrons are inside the nucleus. The atomic number of an atom is the number of protons, and if you subtract the atomic number from the atomic mass you can find the number of neutrons an atom has.
So, the mass of the protons plus the mass of the neutrons, which are both inside the nucleus, equals the atomic mass.
Its <span>234or238 hope dis helped</span>
Answer:
V₂= 33581.4 ft³
Explanation:
Given data:
Initial temperature = -15 °C (-15+273 = 258 k)
Initial volume = 28500 ft³
Final temperature = 31 °C (31+273 = 304)
Final volume = ?
Solution:
According to the Charles's law
Temperature and volume are directly related to each other.
V₁/T₁ = V₂/T₂
V₂ = V₁×T₂ /T₁
V₂ = 28500 ft³ × 304 k / 258 k
V₂ = 8664000 ft³.k/ 258 k
V₂= 33581.4 ft³
Answer:
92.8%
Explanation:
Step 1: Given data
- Mass of lead in the bullet (mPb): 11.6 g
- Mass of tin in the bullet (mSn): 0.5 g
- Mass of antimony in the bullet (mSb): 0.4 g
Step 2: Calculate the total mass of the bullet
The total mass of the bullet is equal to the sum of the masses of the elements that form it.
m = mPb + mSn + mSb = 11.6 g + 0.5 g + 0.4 g = 12.5 g
Step 3: Calculate the mass percentage of Pb in the bullet
We will use the following expression.
%Pb = mPb / m × 100%
%Pb = 11.6 g / 12.5 g × 100% = 92.8%
Analyze the Name of complex Compound.
T<span>etracarbonylplatinum(iv) chloride
So, there are,
4 Carbonyl groups = 4 CO = (CO)</span>₄
1 Platinum Metal = 1 Pt = Pt
Unknown Chloride atoms = ?
In complexes positive part is always named first, so the sphere containing Pt and carbonyl ligands is written first,
[Pt (CO)₄]
The charge on sphere is +4 because CO ligand is neutral, and Pt has a Oxidation state of four as written in name (IV),
So,
[Pt (CO)₄]⁴⁺
Now, in order to neutralize +4 charge we should add 4 Chloride ions, So,
[Pt (CO)₄] Cl₄
