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Jlenok [28]
3 years ago
7

Solve the following quadratic by completing the square. y = x2 + 4x - 2

Mathematics
2 answers:
ycow [4]3 years ago
8 0

Answer:

x = - 2 ± √6.

Step-by-step explanation:

x^2 + 4x - 2 = 0

x^2 + 4x = 2

(x + 4/2)^2 - 2^2 = 2

(x + 2)^2 - 4 = 2

(x + 2)^2 = 6

x + 2 = ± √6

x = - 2 ± √6.

iogann1982 [59]3 years ago
4 0

Answer:

x = √6 - 2 , -√6-2

Step-by-step explanation:

We have ,

=> y = x² + 4x - 2

  • Let y = 0

=> x² + 4x - 2 = 0

=> x² + 2(2)(x) - 2 = 0

=> x² + 2(2)(x) +2² - 2² -2 = 0

=> x² + 2(2)(x) + 2² -4-2 = 0

=> ( x + 2 )² -6 = 0

=> ( x +2)² = 6

=> ( x + 2) = √6

=> x + 2 = ±√6

=> x = √6 - 2 , -√6-2

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Step-by-step explanation:

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If we spin the spinner 10 times, what is the best prediction possible for the number of times it will land on yellow or purple?
kiruha [24]

Answer:

Yellow = 5 times and I think you meant blue since there is no purple so blue = 3 times

Step-by-step explanation:

There is ten in all and half of the spaces are yellow, or 50%. Out of ten times, you should land on it about half, or 5. For blue, there are 3 spaces, or 30%. Out of ten times, you should lamd on it about three.

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If you roll a six sided die three times, how many possible outcomes are there?
Mkey [24]

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Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
4 years ago
If f(x)= |x^3-3| then f(-1) is equivalent to
emmasim [6.3K]

Hello from MrBillDoesMath!

Answer:

4

Discussion:

f(x) =  abs (x^3 - 3)        =>

f(-1) = abs ( (-1)^3 -3 )    =>        (-1)^3 =  -1

f(-1) = abs( -1 -3 )           =>       -1 =3 = -4

f(-1) = abs(-4)               =>

f(-1) = 4

Thank you,

MrB

8 0
4 years ago
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