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4 years ago

Rewrite the radical expression as an expression with rational exponents.

Mathematics

1 answer:

sashaice [31]4 years ago

7 0

The fifth root of x can be expressed as a power of 1/5 this way:

x^(1/5).

Now raise [x^(1/5)] to the 9th power.

[x^(1/5)]^(9)

Multiply the powers to complete the problem.

x^(9/5)

Answer: Choice B.

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Solve the inequality.<br> 4x + 3 < 7 or 3x – 8 > 7<br> -<br> x < [?] or x > [

ss7ja [257]

Answer:

$4x + 3 < 7 \\ 4x + 3 - 3 < 7 - 3 \\ 4x < 4 \ \\ 4x \div 4 < 4 \div 4 \\ x < 1$

$3x - 8 > 7 \\ 3x - 8 + 8 > 7 + 8 \\ 3x > 15 \\ 3x \div 3 > 15 \div 3 \\ x > 5$

6 0

3 years ago

PLEASE HELP!!!!!!!! IMAGE ATTACHED!!!!

erma4kov [3.2K]

Answer:

Step-by-step explanation:

4) (-2,3) ; (-1,-2)

$Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-2-3}{-1-[-2]}\\\\=\frac{-5}{-1+2}\\\\=\frac{-5}{1}\\\\=-5$

5) line is parallel to x-axis. So, slope= 0

6) (1,1) ; (-2, -1)

$Slope=\frac{-1-1}{-2-1}\\\\=\frac{-2}{-3}\\\\=\frac{2}{3}$

6 0

3 years ago

Solve for y 2y - 11 > -19.

Talja [164]

Answer:

Y>-4

Step-by-step explanation:

Add 11 to both sides and divide

3 0

4 years ago

Read 2 more answers

The product shown is a difference of squares. What is the missing constant term in the second factor?

34kurt

Difference of two squares is of the form (a + b)(a - b) or vice-versa. Here, a = -5x and b = 3.
(-5x - 3)(-5x + 3)
Answer: 3

7 0

3 years ago

Read 2 more answers

A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 17 randomly selected pens yield

Leno4ka [110]

Answer:

0.762 = 76.2% probability that this shipment is accepted

Step-by-step explanation:

For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

17 randomly selected pens

This means that $n = 17$

(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)

This is $P(X \leq 2)$ when $p = 0.1$ . So

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{17,0}.(0.1)^{0}.(0.9)^{17} = 0.167$

$P(X = 1) = C_{17,1}.(0.1)^{1}.(0.9)^{16} = 0.315$

$P(X = 2) = C_{17,2}.(0.1)^{2}.(0.9)^{15} = 0.280$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.167 + 0.315 + 0.280 = 0.762$

0.762 = 76.2% probability that this shipment is accepted

8 0

4 years ago