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Answer:
An old bone contains 80% of its original carbon-14 in 1844.6479 years
Step-by-step explanation:
We know that
half life time of C-14 is 5730 years
so, h=5730
now, we can use formula
we can plug back h
and we get
An old bone contains 80% of its original carbon-14
so,
P(t)=0.80Po
we can plug it and then we solve for t
So,
An old bone contains 80% of its original carbon-14 in 1844.6479 years