Answer:
The correct option is <em>B. Cholesterol is non-polar.</em>
Explanation:
Cholesterol is a non- polar substance and due to this property it is an active part of the cell membrane. Cholesterol molecules help to maintain the stability of a cell. When the temperatures are high, cholesterol stops the cell membrane from crystallization. When the temperatures are low, cholesterol reduces the packaging of molecules of phospholipids. As a result, fluid phase is archived by the cell membrane.
Fission, fragmentation, budding, and agamogenesis
The process described which shows the hydrosphere interacting with the lithosphere is river water eroding a rocky bank and carrying silt to the sea which is therefore denoted as option B.
<h3>What is Hydrosphere?</h3>
This is referred to as the combined mass or quantity of water found on the plant such as earth and it comprises of different water bodies such as rivers, seas etc.
Lithosphere on the other hand is referred to as the solid, outer part of Earth which consists of the upper portion of the mantle and the crust in the form of rocks etc.
Water is very important in the ecosystem and is the reason why it is recycled so as to enable its presence which is usually in the form of precipitation. River water which is part of the hydrosphere erodes a rocky bank which forms part of the lithosphere.
Read more about Lithosphere here brainly.com/question/28135333
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Molecules brought in and used in the calvin cycle - Carbon dioxide 
, Ribulose bisphosphate (RuBP)
Molecules produced during the calvin cycle that leave the cycle - a few of the glyceraldehyde-3-phosphate (G3P), NADP+
Molecules used and regenerated within the calvin cycle - most of the Glyceraldehyde-3-phosphate (G3P) , NADPH
<u>Explanation:</u>
Calvin cycle is the light independent reaction that takes place in the stroma of the chloroplast. Calvin cycle uses ATP and NADPH produced during the light reaction. Calvin cycle occurs in 3 steps, they are:
1. Carbon fixation - combines with Ribulose bisphosphate (RuBP) to form 2 molecules of 3-phosphoglyceric acid (3-PGA).
2. Reduction - ATP and NADPH is used to convert 3-PGA into glyceraldehyde-3-phosphate (G3P).
3. Regeneration - some G3P molecule form glucose while other regenerates to form RuBP acceptor.
