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Vaselesa [24]
2 years ago
10

A man with O type blood marries a woman with AB type blood. What are the possible blood types of their offspring?

Biology
2 answers:
tangare [24]2 years ago
6 0

P(O blood)= 0

P(A blood) = 2/4= 1/2

P(B blood) = 1/2

P(AB blood)= 0

i = recessive Gene

IA = dominant Gene

IB = dominant gene

ASHA 777 [7]2 years ago
3 0
B. A blood. Cause the women is AB while the man is O, O being the top tier blood could only boost it to A blood
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<h3>What is an Allele?</h3>

This can be defined as the variant form of a gene. In this scenario, there are two variants which are dominant and recessive allele.

Both parents have to possess the dominant allele for all the offsprings to also have the dominant trait.

Read more about Allele here brainly.com/question/3452155

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Its A :)

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Can you please help me with this?​
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5 0
3 years ago
In a population of plants, the allele for long stems is completely dominant over the allele for short stems. If 35% of the popul
KatRina [158]
Assumptions:
1. Equilibrium has been reached for the allele proportions
2. Absence of <span>evolutionary influences such as </span>mate choice<span>, </span>mutation<span>, </span>selection<span>, </span>genetic drift<span>, </span>gene flow<span> and </span>meiotic drive<span>.
</span>
Defining L=long stem, l=short stem, and L is dominant over l.
f(x) = frequency of allele x  (expressed as a fraction of population)
Then the Hardy-Weinberg equilibrium law applies:
p^2+2pq+q^2=1
where 
f(LL)=p^2
f(Ll)=2pq
f(ll)=q^2

Given f(ll)=0.35=q^2, we have
q=sqrt(0.35)=0.591608
p=1-q=0.408392
=>
f(Ll)
=2pq
=2*0.408392*0.591608=0.483216
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Answer: percentage of heterozygous population is 48.32%
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