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HACTEHA [7]
3 years ago
10

You rent a car for the day and are offered two payment options. With option A you pay $25 flat rate plus $0.15 per mile. With op

tion B you pay a $10 flat rate plus $0.40 per mile. For what amount of miles would the cost of option A be equal to option B
Mathematics
1 answer:
Citrus2011 [14]3 years ago
8 0

Answer:

60 miles.

Step-by-step explanation:

Given:

We rent a car for the day and are offered two payment options.

With option A we pay $25 flat rate plus $0.15 per mile.

With option B we pay a $10 flat rate plus $0.40 per mile.

Question asked:

For what amount of miles would the cost of option A be equal to option B ?

Solution:

<u>Let amount of miles for which the cost of option A be equal to option B = </u>x<u />

For option A, we pay = 25+0.15\times x

For option B, we pay = 10+0.40\times x

Now, to find amount of miles for which the cost of option A be equal to option B, we will equalize the equation to find the value of x

25+0.15x=10+0.40x\\

By subtracting both sides by 10

25-10+0.15x=10-10+0.40x\\15+0.15x=0.40x

By subtracting both sides by 0.15x

15+0.15x-0.15x=0.40x-0.15x\\15=0.25x

By dividing both sides by 0.25

x=60\ miles

Therefore, for 60 miles, the cost of option A will be equal to option B.

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Answer:

10500 dollars

Step-by-step explanation:

350,000 * .03 = 10500

4 0
2 years ago
Can someone help me with these 2
frosja888 [35]

Answer:

Step-by-step Yes it is, assuming we decide to use the Pythagorean Theorem to find the hypotenuse (10) it'll be possible considering the formula is c²=√a²+b²

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c= 10p explanation:

4 0
3 years ago
Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t​
juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t  ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

 

6 0
3 years ago
Solve for x: -1 &lt; x + 3 &lt; 5​
Rus_ich [418]

Answer:

−4<x<2

Step-by-step explanation:

−1<x+3<5

−1+−3<x+3+−3<5+−3  (Add -3 to all parts)

−4<x<2

3 0
3 years ago
Read 2 more answers
I need help with this question
Svetlanka [38]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
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