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Alisiya [41]
2 years ago
15

Simplify: 3[(5-2)3 + 4]

Mathematics
1 answer:
avanturin [10]2 years ago
6 0

Answer:

39

Step-by-step explanation:

1. Subtract the numbers ... 3(3×3+4)

2. Multiply the numbers ... 3(9+4)

3. Add the numbers ... 3×13

4. Multiply the numbers ... 39

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Given that 35.8 x 4.23= 151.434<br>write down a division sum with an answer of 423.​
Nina [5.8K]

Answer:

  151434/358 = 423

Step-by-step explanation:

Every product with non-zero factors can be written as an equivalent division relation.

  a·b = c   ⇒   a = c/b

Here, we have 35.8 × 4.23 = 151.434. This can be written as the equivalent ...

  4.23 = 151.434/35.8

We can multiply this by 100 to get a division relation with a quotient of 423:

  423 = 15143.4/35.8

If we want, we can move the decimal points another place to the right to get ...

  151434/358 = 423

7 0
2 years ago
Why the denator in the numerator stay the same
nika2105 [10]
Because it is like having a unit of measurement that is set
lets say that in a certain country, one serving of bread is 1/2 of the standard loaf
and if you have 3 servings, you have 3/2 loaf so the bottom number tells you how many parts out of 1 whole you have
8 0
3 years ago
Given that 12 , 3 is on the graph of f(x) find the corresponding point for the function
mariarad [96]
(12,24)
Hope it helps love.
-Joker7721
8 0
3 years ago
Dion spent m minutes on his math homework, g minutes on his german homework and 30 minutes on his biology homework. In total he
Blizzard [7]

m + g + 30 = t

If m = 40 and t = 95,

g = t - m - 30 = 95 - 40 - 30 = 25.

8 0
3 years ago
Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

5 0
3 years ago
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