Graph the image of triangle PQR after a reflection across the line y = 2
1 answer:
Answer: Refer to the diagram below
- P ' is at (-7, 9)
- Q ' is at (1, 9)
- R ' is at (-6, 4)
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Explanation:
The diagram shows how point R moves to R'. We move up 2 units going from R(-6,0) to (-6,2). This lands us on the line of reflection. Then we move another 2 units up to land on (-6,4) which is the location of point R'.
The other points P and Q follow the same idea. Though the distances will be different from R. For P and Q, we'll move 7 units up to arrive at the line of reflection, then another 7 units to arrive at the proper locations of P' and Q', which are (-7,9) and (1,9) respectively.
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Answer:
(C)4
Step-by-step explanation:
Given the line:
The gradient of the line,
A line perpendicular to the given line will have a gradient, (by definition of perpendicularity).
Therefore, a perpendicular line that passes through the point (4,1) is:
Comparing with the slope-intercept form y=mx+x, the slope of the perpendicular line, b=4.