Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.
<u>Solution:</u>
Let us assume that x is speed of slower eastbound cyclist
So, x+3 will be the speed of faster westbound cyclist
We know that distance is the product of speed and time. That is,
West-bound DATA:
Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles
East-bound DATA:
Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles
On solving,
Distance apart = 162
So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be 
Answer:
-12x^2+46x-6
Step-by-step explanation:
combine like tens and subtract then from eachother
Step-by-step explanation:
Using the properties of logarithms, the left side of the equation becomes
while the right hand side becomes
so we end up with
Answer:
v = -8i - 6j
Step-by-step explanation:
The starting point is (9, 9)
The direction of the vector is the direction of the arrowhead.
The i is the horizontal component.
The j is the vertical component.
Therefore, to go from the start to the end of the line, we need to travel negative 8 units (horizontally) and negative 6 units (vertically).
Therefore, v = -8i - 6j
Answer: give me an explanation because im confused
Step-by-step explanation:
