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3 years ago

5

if the measure of the third angle of the triangle is 20 more than three times the measure of either of the other two angles, fin

d the measure of each angle of the triangle

1 answer:

valentina_108 [34]3 years ago

5 0

You should multiply 20 time 8 to get your answer

You might be interested in

Jim was thinking of a number. Jim adds 20 to it, then doubles it and gets an answer of 99.2. What was the original number?

azamat

Alright, lets get started.

Jim was thinking of a number.

Suppose the number Jim was thinking, is x.

Jim adds 20 to it means number will be = $x+20$

And Jim doubles it, means $2*(x+20)$

Jim gets 99.2 and as per us, he gets $2*(x+20)$

So, making them equal

$2(x+20)=99.2$

$2x+40=99.2$

Subtracting 40 in both sides

$2x+40-40=99.2-40$

$2x=59.2$

$x=29.6$

It means the original number is 29.6. : Answer

Hope it will help :)

6 0

3 years ago

1 fourth B minus 10 equals 7

creativ13 [48]

$\frac{1}{4}$ b - 10 = 7
Take 10 to the other side.

$\frac{1}{4}$ b = 17

Multiply by 4 to isolate b
$\frac{1}{4}$ b × 4 = 17 × 4

4 and 4 cancels out

b = 68

3 0

3 years ago

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

<u>Addition: </u>

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

<u>Multiplication: </u>

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .

For example, the multiplication of these two binomials is:

$(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2$

Similarly, the multiplication of two complex numbers is:

$(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i$

8 0

3 years ago

-2(x-2)=-16 answer.

REY [17]

Answer:

-2x+4=-16

-2x = -16-4

-2x = -20

x = -20/-2

x = 10

3 0

3 years ago

Read 2 more answers

How do you solve the equation <br> <img src="https://tex.z-dn.net/?f=3%28x%2B8%29%3D17" id="TexFormula1" title="3(x+8)=17" alt="

trapecia [35]

3(x + 8) = 17....distribute the 3 thru the parenthesis
3x + 24 = 17...subtract 24 from both sides
3x = 17 - 24
3x = -7...divide both sides by 3
x = -7/3 or -2 1/3 <===

3 0

3 years ago