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3 years ago

5

if the measure of the third angle of the triangle is 20 more than three times the measure of either of the other two angles, fin

d the measure of each angle of the triangle

1 answer:

valentina_108 [34]3 years ago

5 0

You should multiply 20 time 8 to get your answer

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2a + 4b + c =5 <br> x =-2 <br><br> a - 4b = -6<br> y=1

cricket20 [7]

There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10 [2] b-c=15 [3] a-2b+c=-5 Equations Simplified or Rearranged :<span><span> [1] 2a + c = -10 </span><span> [2] - c + b = 15 </span><span> [3] a + c - 2b = -5 </span></span>Solve by Substitution :

// Solve equation [3] for the variable c

<span> [3] c = -a + 2b - 5 </span>

// Plug this in for variable c in equation [1]

<span><span> [1] 2a + (-a +2?-5) = -10 </span><span> [1] a = -5 </span></span>

// Plug this in for variable c in equation [2]

<span><span> [2] - (-? +2b-5) + b = 15 </span><span> [2] - b = 10 </span></span>

// Solve equation [2] for the variable ?

<span> [2] ? = b + 10 </span>

// Plug this in for variable ? in equation [1]

<span><span> [1] (? +10) = -5 </span><span> [1] 0 = -15 => NO solution </span></span><span>No solution</span>

3 0

3 years ago

What’s the volume of a cylinder with a radius of 1 and height of 3ft?

Dafna1 [17]

Answer:

9.42

Step-by-step explanation:

V=pir2h

(pi, radius squared, height)

hope this helped!

6 0

3 years ago

Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen

Jobisdone [24]

Parameterize $S$ by the vector function

$\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k$

so that the normal vector to $S$ is given by

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}$

In this case, the normal vector is

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k$

with magnitude $\sqrt{1^2+2^2+1^2}=\sqrt6$ . The integral of $f(x,y,z)=e^z$ over $S$ is then

$\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx$

where $T$ is the region in the $x,y$ plane over which $S$ is defined. In this case, it's the triangle in the plane $z=0$ which we can capture with $0\le x\le8$ and $0\le y\le\frac{8-x}2$ , so that we have

$\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}$

5 0

3 years ago

Enter a fraction that is equivalent to 1/5 with a numerator of 8.

photoshop1234 [79]

Answer:

lol imagine

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the midpoint between 3.99 and 4

asambeis [7]

Answer:

3.995

Step-by-step explanation:

A midpoint is defined as a point that is exactly in the middle between two other points. The midpoint between two numbers is the number exactly in the middle of the two numbers. Calculating the midpoint is the same thing as calculating the average of two numbers. Therefore, you can calculate the midpoint between any two numbers by adding them together and dividing by two.

6 0

3 years ago