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ivanzaharov [21]
3 years ago
6

Find an equation of the line passing through the point (2, -3) and has slope -4. Then rewrite your linear equation in the slope-

intercept function form f(x) = mx+b
Mathematics
1 answer:
Tresset [83]3 years ago
8 0

Answer:

y=-4x+5

Step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

-3. -3

y=-4x+5

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7th grade math help me plzzz
matrenka [14]

Answer:

a. -14

b. -150

c. -51

d. -2

e. 3

f. 5

8 0
3 years ago
Use the cumulative normal distribution table to find the z-scores thqt bound the middle of 68% of theje area under the stanrard
padilas [110]

Answer:

Z scores between -0.995 and 0.995 bound the middle 68% of the area under the stanrard normal curve

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Middle 68%

Between the 50 - (68/2) = 16th percentile and the 50 + (68/2) = 84th percentile.

16th percentile:

X when Z has a pvalue of 0.16. So X when Z = -0.995

84th percentile:

X when Z has a pvalue of 0.84. So X when Z = 0.995.

Z scores between -0.995 and 0.995 bound the middle 68% of the area under the stanrard normal curve

7 0
3 years ago
Assume that military aircraft use ejection seats designed for men weighing between 141.8 lb and 218 lb. If​ women's weights are
Mariulka [41]

Answer:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(173.6,49.8)  

Where \mu=173.6 and \sigma=49.8

We are interested on this probability

P(141.8

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

8 0
3 years ago
Sibusiso's car consumes petrol at a rate of 7,6 l/100km. The petrol tank in his car holds 65litres. How far can he ride on a ful
Delicious77 [7]

Answer:

6 +67 _^76 + 9 x 2087 - 9012 = 1000

Step-by-step explanation:

98 + 2000 - 76 = 1000

5 0
2 years ago
The graph represents the cost of a subscription to a newspaper
andrezito [222]
B- $7.50. Take 30 and divide it by 4, and you get your weekly subscription cost.
3 0
3 years ago
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