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2 years ago

Use the graph above to determine which of the following ordered pairs is in quadrant II.

Mathematics

1 answer:

Licemer1 [7]2 years ago

8 0

The answer is (4,-1)

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3x + 11 - 2y + 4x - 6 + 5y <br><br> please solve!!! just simplify by combining like terms

rusak2 [61]

the answer to your question is
7y+7x+5

6 0

3 years ago

Read 2 more answers

Suppose the radius of a circle is 8. What is its area?

monitta

The Formula to find the Area of a circle using the radius is:
$A = \pi r^2$

r = 8
So:
$A = \pi r^2$
$A = \pi 8^2$
$A = \pi64$

And you get about 201.06193

So, the area of a circle with a radius of 8 is about 201.06

Hope this Helps :)

3 0

3 years ago

Please include work!

geniusboy [140]

Answer:

x = ± 4

y = - 2

Step-by-step explanation:

y = 0.5x² - 10 ------------------------(I)

y = -x² + 14 ------------------------(II)

Substitute the y value in equation (II)

0.5x² - 10 = -x² + 14 {Add x² to both sides}

0.5x² + x² -10 = 14 {combine like terms}

1.5x² - 10 = 14 {Add 10 to both sides}

1.5x² = 14 + 10

1.5x² = 24 {Divide both sides by 1.5}

1.5x²/1.5 = 24/1.5

x² = 16

x = ±4

Substitute x = 4 in (I)

y = 0.5 * 4² - 10

= 0.5*16 - 10

= 8- 10

y = -2

Substitute x = -4 in (I)

y = 0.5 * (-4)² - 10

= 0.5*16 - 10

= 8- 10

y = -2

5 0

3 years ago

What is the rule input numbers are 17 18 _ 28_40

Lelu [443]

19 27 28 29 30 315 64 29 46 is the
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4 0

3 years ago

Half of a set of the parts are manufactured by machine A and half by machine B. Ten percent of all the parts are defective. Six

baherus [9]

Answer:

The probability that a part was manufactured on machine A is 0.3

Step-by-step explanation:

Consider the provided information.

It is given that Half of a set of parts are manufactured by machine A and half by machine B.

P(A)=0.5

Let d represents the probability that part is defective.

Ten percent of all the parts are defective.

P(d) = 0.10

Six percent of the parts manufactured on machine A are defective.

P(d|A)=0.06

Now we need to find the probability that a part was manufactured on machine A, and given that the part is defective :

$P(A|d) =\frac{P(A \cap d)}{P(d)}$

$P(A|d) =\frac{P(d|A)\times P(A)}{P(d)}\\P(A|d)= \frac{0.06\times 0.5}{0.10}$

$P(A|d)= 0.3$

Hence, the probability that a part was manufactured on machine A is 0.3

8 0

3 years ago