What is the answer to the problem

Laura created a website to create T-shirts. In the first month she put up her website she had only a single T-shirt order. Each

kiruha [24]

Laura received 144 orders over the first year

Solution:

Given function is:

f(n) = 2n - 1

Where, "n" is the month

In the first month she put up her website she had only a single T-shirt order

f(1) = 2(1) - 1 = 2 - 1

f(1) = 1

There are 12 months in a year

For the second month, and third month and so on, substitute n = 2, 3 and so on

f(2) = 2(2) - 1 = 4 - 1 = 3

f(3) = 2(3) - 1 = 6 - 1 = 5

f(4) = 2(4) - 1 = 8 - 1 = 7

f(5) = 2(5) - 1 = 10 - 1 = 9

f(6) = 2(6) - 1 = 12 - 1 = 11

f(7) = 2(7) - 1 = 14 - 1 = 13

f(8) = 2(8) - 1 = 16 - 1 = 15

f(9) = 2(9) - 1 = 18 - 1 = 17

f(10) = 2(10) - 1 = 20 - 1 = 19

f(11) = 2(11) - 1 = 22 - 1 = 21

f(12) = 2(12) - 1 = 24 - 1 = 23

Thus total orders received over first year:

Total orders = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

Total orders = 144

Thus she received 144 orders over the first year

8 0

2 years ago

Find the distance, c, between (–3, –1) and (3, 2) on the coordinate plane. Round to the nearest tenth if necessary ??

astra-53 [7]

Point distance formula:

d=√((x_2-x_1)²+(y_2-y_1)²)

Substitute

d=√((3-(-3))²+(2-(-1)²)

Simplify

d=√((6)²+(3)²)

d=√(36+9)

d=√(45)

-Hunter

8 0

2 years ago

Read 2 more answers

Reduce to the lowest terms 1. 4x^3 y^4 / -8xy^2 2. 3m^2-3n^2 / 6m+6n

lawyer [7]

1.
$\dfrac{4x^{3}y^{4}}{-8xy^{2}}=\dfrac{4}{-8}\cdot x^{3-1}y^{4-2}=\dfrac{-x^{2}y^{2}}{2}$

2.
$\dfrac{3m^{2}-3n^{2}}{6m+6n}=\dfrac{3}{6}\cdot \dfrac{(m+n)(m-n)}{m+n}=\dfrac{m-n}{2}$

3 0

3 years ago

I need help again.Here is the question, Distance = Rate x Time What was my rate of speed if it took me 3.5 hours to travel 210 m

Nimfa-mama [501]

Answer:

60

Step-by-step explanation:

210÷3.5=60

3.5x60=210

Hope this helps!

: )

3 0

3 years ago

Prove that the diagonals of a rectangle bisect each other. the midpoint of is _____

Deffense [45]

In this attached picture, we can prove that triangles AOB and COD are congruent. ∠CDO and ∠ABO are equal because they are alternate angles. Similarly, ∠OAB and ∠OCD are equal because they are alternate angles, as well. We have a rectangle and in the rectangle, opposite sides are equal; AB = CD. Then, because of Angle-SIde-Angle principle, we can say that triangles AOB and COD are equal. If triangles are congruent, then OD = OB and OC = AO. Applying congruency to the triangles ACD and BCD, we can see that these triangles are also congruent. It means that the diagonals are equal. Since, OD = OB and OC = AO, it proves that the point O simultaneously is the midpoint and intersection point for the diagonals.

8 0

2 years ago