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Maslowich
3 years ago
8

What number goes on top?

Mathematics
1 answer:
Artemon [7]3 years ago
7 0

Answer:

33

Step-by-step explanation:

each upper cell is the sum of the two cells under it. For example 4 and 5 make 9 so 16+17=33

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I need to find x in number twenty two
Ber [7]

4x - 1 = 8 + 8

4x - 1 = 16

4x = 17

4x/4 = 17/4

x = 4.25

3 0
3 years ago
Read 2 more answers
A store offers four different brands of a product. It decides to eliminate the brand that is most likely to be returned. The tab
STatiana [176]

Answer: brand C

Step-by-step explanation:

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6 0
3 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
HELP PLEASEEEE!!!!!!
meriva

Answer:

30

Step-by-step explanation:

Since there are 5 possible outcomes for the cards, and 6 possible outcomes for the die, there are a total of 5*6=30 outcomes possible. Hope this helps!

3 0
3 years ago
Which step is incorrect and what is the correct answer?
Anit [1.1K]

Answer:

Step 4, x = 3

Step-by-step explanation:

Step 4 was wrong, instead of 6x = 6, it should be 6x = 18. They shoudl've added 6 to both sides instead of subtracting 6 as ur trying to cancel out the 6 on the left side of the equation. So:

6x = 18

x = 3

7 0
3 years ago
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