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3 years ago

Hello please help i’ll give brainliest

Mathematics

1 answer:

Vesnalui [34]3 years ago

7 0

Answer:

here you go your welcome

Step-by-step explanation:

after however

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ILL MARK BRAINILEST (100 POINTS) !!! Factor the polynomial 7xy + 14x − 35y − 70 completely. 7(2x − 5)(y + 2) 7(x − 5)(y + 2) 7(x

Vlad [161]

Answer:

B. 7(x − 5)(y + 2)

Explanation:

A. 7(2x − 5)(y + 2) = 14xy + 28x − 35y − 70 (Wrong)

B. 7(x − 5)(y + 2) = 7xy + 14x − 35y − 70 (Correct)

C. 7(x − 2)(y + 5) = 7xy + 35x− 14y − 70 (Wrong)

D. 7(x − 10)(y + 2) = 7xy + 14x − 70y − 140 (Wrong)

8 0

2 years ago

Read 2 more answers

Sarah was raising money for a fundraiser. Her fundraising goal was $40. What would 50% of her fundraising goal be??

Delvig [45]

Answer:

$20

Step-by-step explanation:

50% of Fundraising goal= 0.5 x $40

= $20

4 0

3 years ago

If X and Y are independent continuous positive random

Leni [432]

a) $Z=\frac XY$ has CDF

$F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy$

where the last equality follows from independence of $X,Y$ . In terms of the distribution and density functions of $X,Y$ , this is

$F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy$

Then the density is obtained by differentiating with respect to $z$ ,

$f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy$

b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Differentiating gives the associated PDF,

$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

and

$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0

3 years ago

Find the distance between the two points. 3. (-3, -1), (6, 2)

lorasvet [3.4K]

Answer:

Step-by-step explanation:

3 0

3 years ago

Anji bought 4 shirts for $56.80. She later bought a shirt for $19.20. What was the mean cost of all the shirts in dollars?

MakcuM [25]

Answer:

$15.20

Step-by-step explanation:

When you are asked to find the mean, you would add up the costs of the shirts and then divide them by however many shirts she got.

56.80 + 19.20 = 76

76 ÷ 5 = 15.20

Thus the mean cost is $15.20

Hope this helped!

7 0

3 years ago