The relationship between 5.34×105 and 5.34×10−2 would be that the former number is 10000000 times larger than the latter value. We can obtain this by dividing 5.34×105 and 5.34×10−2 where the quotient would be 10000000. Hope this answers the question. Have a nice day.
(-1, 2)
So the original point is (3, 4), when you move to the left or right, it changes the x value. When moving it to the right, you add the amount. When moving to the left, you subtract the amount
So after translating the point 4 units to the left, it should be (-1, 4).
Now, you have to move down. When moving up and down, you add or subtract to the y value. When moving up, you add to the amount. When moving down, you subtract the amount.
After subtracting 2, you should be at (-1, 2)
Small number =X
mid number = 3X-4
large number = 3x
X+3X-4+3X=24
7X-4=24
7X-4+4=24+4
7X=28
X=28/7
X=4
S=4
M=3(4) -4=12-4=8
L=3(4)=12
The numbers are 4,8 and 12
Answer:
The equation has no solutions .
Step-by-step explanation:
Given as :
<u>The linear equation is </u>
(24 -16 x) =
(18 x -27)
Or,
×24 -
× 16 x =
× 18 x -
× 27
Or,
×24 -
× 16 x =
× 18 x +
× 27
Or,
-
=
+
Or, 3 × 6 - 3 × 4 x = - 2 × 6 x + 2 × 9
Or, 18 - 12 x = - 12 x + 18
Or, 18 - 18 = - 12 x + 12 x
or, 0 = 0
∵ The linear equation has no variables , so the equation has no solution
Hence,The equation has no solutions . Answer
Answer. First option: t > 6.25
Solution:
Height (in feet): h=-16t^2+729
For which interval of time is h less than 104 feet above the ground?
h < 104
Replacing h for -16t^2+729
-16t^2+729 < 104
Solving for h: Subtracting 729 both sides of the inequality:
-16t^2+729-729 < 104-729
-16t^2 < -625
Multiplying the inequality by -1:
(-1)(-16t^2 < -625)
16t^2 > 625
Dividing both sides of the inequality by 16:
16t^2/16 > 625/16
t^2 > 39.0625
Replacing t^2 by [ Absolute value (t) ]^2:
[ Absolute value (t) ]^2 > 39.0625
Square root both sides of the inequality:
sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)
Absolute value (t) > 6.25
t < -6.25 or t > 6.25, but t can not be negative, then the solution is:
t > 6.25