All categories

3 years ago

A class has 24 people and 1/6 of them have blue eyes what fraction of class has blue eyes using 24 as denominator

2 answers:

8 0

Answer: 4/24

Explanation: Multiply the amount of people in the class by the fraction of the class that has blue eyes.

The amount of people in class who have blue eyes: 24 x 1/6= 4

24 represents the total amount of people in the class. And 4 represents the amount of people in the class with blue eyes. You set up the fraction with the amount of blue-eyed people on top, as the numerator. And the total number of people as the denominator.

Once again here’s what it should look like: 4/24

Hope this helps!

valkas [14]3 years ago

5 0

Answer:

16/24

Step-by-step explanation:

4/6 = 16/24

You might be interested in

Dean works 47.75 hours in one week. He is paid hourly at a rate of $16.50. What is Dean’s total pay for the week? Round your ans

Rus_ich [418]

787.90...............................i think

7 0

3 years ago

Read 2 more answers

I have 6 surfaces 2 of my surfaces are smaller then the others I can stand up tall what shape am I

Arada [10]

This shape would be a rectangular prism, with 4 rectangular sides, and 2 square or smaller rectangular sides.

An example of a rectangular prism would be a brick. It has 4 sides that are perfectly alike, then two other sides that are like each other.

5 0

3 years ago

Read 2 more answers

Is 45 a multiple of 4? Explain your answer Lmk ASAP

arsen [322]

No 45 is a multiple for 5

6 0

3 years ago

Read 2 more answers

Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

7 0

3 years ago

An office that dispenses automotive license plates has divided its customers into categories to level the office workload. Custo

grigory [225]

Answer:

UNIF(2.66,3.33) minutes for all customer types.

Step-by-step explanation:

In the problem above, it was stated that the office arranged its customers into different sections to ensure optimum performance and minimize workload. Furthermore, there was a service time of UNIF(8,10) minutes for everyone. Since there are only three different types of customers, the service time can be estimated as UNIF(8/3,10/3) minutes = UNIF(2.66,3.33) minutes.

6 0

3 years ago