The answer is 9
both 81 and 63 are dividable by 9, and nothing higher


Step-by-step explanation:
if 'c' is meant to be another 'x' the answer is
(3, 1)
x = 3,y = 1
Answer:
k = -12/77
Step-by-step explanation:
OG problem: k(3k−6)−7k(6k+10)=12
Step-by-step:
3k - 6k - 42k - 70k = 12
-3k - 42k - 70k = 12
-7k - 70k = 12
-77k = 12
k = -12/77
Answer:
4.5yards
Step-by-step explanation:
$40 =5yards
$36 =?
36*5=180÷40
=4.5yards
Answer:
a) P(Y > 76) = 0.0122
b) i) P(both of them will be more than 76 inches tall) = 0.00015
ii) P(Y > 76) = 0.0007
Step-by-step explanation:
Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
To find - (a) If a man is chosen at random from the population, find
the probability that he will be more than 76 inches tall.
(b) If two men are chosen at random from the population, find
the probability that
(i) both of them will be more than 76 inches tall;
(ii) their mean height will be more than 76 inches.
Proof -
a)
P(Y > 76) = P(Y - mean > 76 - mean)
= P(
) >
)
= P(Z >
)
= P(Z >
)
= P(Z > 2.25)
= 1 - P(Z ≤ 2.25)
= 0.0122
⇒P(Y > 76) = 0.0122
b)
(i)
P(both of them will be more than 76 inches tall) = (0.0122)²
= 0.00015
⇒P(both of them will be more than 76 inches tall) = 0.00015
(ii)
Given that,
Mean = 69.7,
= 1.979899,
Now,
P(Y > 76) = P(Y - mean > 76 - mean)
= P(
)) >
)
= P(Z >
)
= P(Z >
))
= P(Z > 3.182)
= 1 - P(Z ≤ 3.182)
= 0.0007
⇒P(Y > 76) = 0.0007