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lakkis [162]
2 years ago
7

Can someone please check my answer

Mathematics
2 answers:
Mrac [35]2 years ago
8 0

Answer:

Step-by-step explanation:

you are correct.

lyudmila [28]2 years ago
6 0

Answer:

less

Step-by-step explanation:

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alukav5142 [94]
The product of 5 and 2/3 is 5.6666
5 0
3 years ago
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Someone please pass the answers to this
arsen [322]

Answer/Step-by-step explanation:

1. The figure is composed of a triangle and a rectangle.

Area of the triangle = ½*base*height

base = 4 ft

height = 12 - 8 = 4ft

Area of triangle = ½*4*4 = 8 ft²

Area of rectangle = length * width

Length = 8 ft

Width = 4 ft

Area of rectangle = 8*4 = 32 ft²

✔️Area of the figure = 8 + 32 = 40 ft²

2. The figure is composed of a semicircle and a triangle

Area of the semicircle = ½(πr²)

radius (r) = 3 cm

π = 3

Area = ½(3*3²) = 13.5 cm²

Area of triangle = ½*base*height

base = 3*2 = 6 cm

height = 6 cm

Area = ½*6*6 = 6 cm²

✔️Area of the figure = 13.5 + 6 = 19.5 cm²

5 0
3 years ago
May runs 10/4 miles everyday after school. Beth says she runs further because she runs 5/2 miles everyday after school. Is her s
Andrew [12]

Answer:

Her statement is not correct.

Step-by-step explanation:

It is not correct because if you simplify 10/4 it comes out to 5/2 therefore 5/2=5/2.

Beth and May run the same amount.

4 0
3 years ago
A trap to catch fruit flies uses a cone in a jar. The cone is shown with a height of 10 centimeters (cm) and a radius of 6 centi
Tresset [83]

Answer:

120 pi

Step-by-step explanation:

a. 1/3pi(6)^2(10)

just plug them into the calculator using pi.

b. pi is more accurate because you aren't round to 3.14. If you use 3.14 your answer will be rounded and not an exact number.

5 0
3 years ago
Find the standard form of the equation of the parabola with the given characteristics. Vertex: (-6, 1); focus: (-6, 0)
GREYUIT [131]

Answer: (x+6)^2=-4(y-1)

Step-by-step explanation:

Given

Vertex of the parabola (-6,1)

Focus of the parabola (-6,0)

As the x coordinate of vertex and focus is same and focus lie below the vertex, therefore the parabola is the type of

(x+6)^2=-4a(y-1)

distance between Vertex and focus is 1 unit

\therefore a=1

Parabola becomes

\Rightarrow (x+6)^2=-4(y-1)

8 0
3 years ago
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