The probability is 1/9
<em>We want to find the </em><em>probability </em><em>that the first drawn ball is even, and the second is odd.</em>
The probability of randomly drawing an even ball will be equal to the quotient between the number of balls with even numbers and the total number of balls in the bucket.
We have a total of 10 balls (4 red ones and 6 black ones)
and 5 of these have even numbers (2, 4, 6, 8, 10)
Then the probability of drawing a ball with an even number first is:
p = 5/10 = 1/5
now we want to get a ball with an odd number.
notice that we already got a ball with an even number and we did not replace it, so now there are 9 balls left in the bucket, 5 odd ones, and 4 even ones.
The probability of getting an odd ball is computed in the same way thana above, as the quotient between the number of balls with odd numbers (5) and the total number of balls in the bucket (9)
q = 5/9
The joint probability (the probability that these two events happen together) is equal to the product of the individual probabilities, so we will get:
P = p*q = (5/9)*(1/5) = 1/9
The probability is 1/9
If you want to learn more about this topic, you can read:
brainly.com/question/24280250
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