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svetlana [45]
2 years ago
15

4+3.2)×(9−2)+2.5 No links hellp meeee!

Mathematics
1 answer:
iogann1982 [59]2 years ago
5 0

Answer:

52.9

??

Step-by-step explanation:

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The line x+ 2y = 9 intersects the curve xy + 18 = 0 at the points A and B. Find the coordinates of A and B.
victus00 [196]
Subtracting the second equation by 18 on both sides, we have xy=-18. Next, we divide both sides by x to get y=-18/x  Plugging that into the first equation, we have x+2(-18/x)=9. Multiplying both sides by x, we get x^2-36=9x. After that, we subtract both sides by 9x to get x^2-9x-36=0. Finding 2 numbers that add up to -9 but multiply to -36, we do a bit of guess and check to find the answers to be -12 and 3. Factoring it, we get 
x^2-12x+3x-36=x(x-12)+3(x-12)=(x+3)(x-12). To find the x values, we have to find out when 0=(x+3)(x-12). This is simple as when you multiply 0 with anything, it is 0. Therefore, x=-3 and 12. Plugging those into x=-18/y, we get x=-18/y and by multiplying y to both sides, we get xy=-18 and then  we can divide both sides by x to get -18/x=y. Plugging -3 in, we get -18/-3=6 and by plugging 12 in we get -18/12=-1.5. Therefore, our points are (-3,6) and (12, -1.5)
6 0
3 years ago
Help me in this one pls I give 15 pts
scoundrel [369]

Answer:

23.7555090109  

Step-by-step explanation:  

sin= opposite/hypotenuse  

sin(53) = BC/60cm  

BC= sin(53)*60 = 23.7555090109

6 0
3 years ago
10 points need help asap
alexandr402 [8]

Answer:

Cross section is the term name given to the front of any prism. SO, they are only found in a prism. They are recognized as the side/face that appears twice in a prism, and the shape have a visible length between these 2, known as the height

Step-by-step explanation:

Hope this helps

4 0
3 years ago
If x = 7+3 root 5 by 7 - 3 root 5 , find the value of x^2 + 1 by x^2
Vesnalui [34]

Answer:

6 because why not

Step-by-step explanation:

6 0
2 years ago
Find a third degree polynomial function of the lowest degree that has the zeros below and whose leading coefficient is one.
Tanzania [10]

Answer:

The polynomial function of the lowest degree that has zeroes at -1, 0 and 6 and with a leading coefficient of one is p(x) = x^{3}-5\cdot x^{2}-6\cdot x.

Step-by-step explanation:

From Fundamental Theorem of Algebra, we remember that the degree of the polynomials determine the number of roots within. Since we know three roots, then the factorized form of the polynomial function with the lowest degree is:

p(x) = (x-r_{1})\cdot (x-r_{2})\cdot (x-r_{3}) = 0 (1)

Where r_{1}, r_{2} and r_{3} are the roots of the polynomial.

If we know that r_{1} = -1, r_{2} = 0 and r_{3} = 6, then the polynomial function in factorized form is:

p(x) = (x+1)\cdot x \cdot (x-6) (2)

And by Algebra we get the standard form of the function:

p(x) = x\cdot (x+1)\cdot (x-6)

p(x) = x\cdot (x^{2}-5\cdot x -6)

p(x) = x^{3}-5\cdot x^{2}-6\cdot x (3)

The polynomial function of the lowest degree that has zeroes at -1, 0 and 6 and with a leading coefficient of one is p(x) = x^{3}-5\cdot x^{2}-6\cdot x.

6 0
2 years ago
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