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3 years ago

Use the equation y = 7x to complete the table. What are the missing values of

Mathematics

1 answer:

Basile [38]3 years ago

7 0

Answer:

D) When x=2, y=14
When x=4, y=28

Step-by-step explanation:

By using slope= y2-y1/x2-x1

I get (1,7) and (3,21) from the table

slope= 21-7/3-1= 14/2= 7

Then I plug in the values into y=mx+b

7= 7(1) +b

b= 0

Getting an equation of y=7x

When x= 2

y= 7(2)= 14

When x= 4

y= 7(4)= 28

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4 years ago

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Questions

loris [4]

Answer:

4 cm

Step-by-step explanation:

Both the area of a square and the area of a rectangle can be found by multiplying length x width. Because all of the sides of a square are equal, you get 64 when you multiply two sides together to find the area.

Since the rectangle has the same area as the square, that means the rectangle's width has to be a number that equals 64 when multiplied by 16.

So, 64/16 equals 4.

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6 0

3 years ago

betty has a cow.the cow produces 5 liters of milk in a day. if the cows diet is improved the cow will produce 200% more milk.how

DanielleElmas [232]

We can start by setting out what we know simply.

Cow produces 5 liters a day.

The cow can make 200% more.

200% of 5, is 10.

If he makes 200% more, he will make 10 liters more.

He already makes 5.

10+5 is what he will make.

FINAL ANSWER:

"If the cow's diet is improved, the cow will produce 15 liters of milk in a day."

5 0

3 years ago

You are running a race. The probability that you win is 3/5. What is the probability that you lose at most 2 out of your 6 races

Veronika [31]

Answer:

The probability that you lose at most 2 out of your 6 races is 0.54432.

Step-by-step explanation:

We are given that you are running a race. The probability that you win is 3/5.

There are total of 6 races.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 6 races

r = number of success = at most 2 lost

p = probability of success which in our question is probability that

you lose a race = 1 - (3/5) = 2/5 or 0.4

Let X = Number of races lost

So, X ~ Binom(n = 6, p = 0.40)

Now, the probability that you lose at most 2 out of your 6 races is given by = P(X $\leq$ 2)

P(X $\leq$ 2) = P(X = 0) + P(X = 1) + P(X = 2)

= $\binom{6}{0} \times 0.40^{0} \times (1-0.40)^{6-0} + \binom{6}{1} \times 0.40^{1} \times (1-0.40)^{6-1} + \binom{6}{2} \times 0.40^{2} \times (1-0.40)^{6-2}$

= $1 \times1 \times 0.60^{6} + 6 \times 0.40^{1} \times 0.60^{5} +15\times 0.40^{2} \times 0.60^{4}$

= 0.54432

7 0

3 years ago