AECD is a parallelogram but I don’t get it
Step-by-step explanation:
if there is nothing missing, we have
x + 25/-8 = -6
in order to compare or add or subtract fractions, we need to bring them all to the same denominator (bottom part).
remember, integer numbers are fractions too. like here
-6 = -6/1
25/-8 = -25/8
so, how can we bring -6/1 to .../8 ?
by multiplying 1 by 8.
but we cannot multiply only the denominator by 8. otherwise we would suddenly have
-6/8
and is -6/8 = -6/1 ? no, certainly not.
to keep the original value of the fraction we have to do the same multiplication also with the numerator (top part).
so, we actually do
-6/1 × 8/8 = -48/8
with this little trick we have now .../8 to operate with, and our transformed fraction has still the same value
-6/1 = -48/8 indeed.
so, we have
x + -25/8 = -48/8
x - 25/8 = -48/8
x = -48/8 + 25/8 = -23/8
the correct answer should be (b) 6 is extraneous.
If you look at the second row of the solution you see (x-6) as a factor in one of the denominators. That's a problem: if 6 were a solution this denominator would become 0. But denominators being 0 is bad (undefined), so while 6 comes out of the algebraic manipulation as a solution, it is invalid, or extraneous.
-3 is a fine solution.
Each square represents 8
If it is 10×10 then there is 100 squares
800÷100=8
Answer: 6*Q= 6Q or 6*Q= y
Step-by-step explanation:
The product is the answer to a multiplication problem, therefore 6*Q will be the first part.
The second part will be the answer. Normally, this would be represented just by 6Q, but you can use another letter to represent it. We'll use y for an example.
6*Q= 6Q
or
6*Q= y
