Every triangle is 180 degrees, so each other angle should have 20
5-4 //jzbbxbxbzbbsjd jsjdjcn ñandú
Answer: 4
Step-by-step explanation:
u find it using the formula r= root 3 V/pi*Height
in this case it is root 3*167.55/pi*10 which is equal to 3.99998 and that rounds to 4
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
How large of a sample of state employees should be taken if we want to estimate with 98% confidence the mean salary to be within $2,000? The population standard deviation is assumed to be $10,500. z-value for 98% confidence level is 2.326.
Answer:
Sample size = n = 150
Step-by-step explanation:
Recall that the margin of error is given by
![$ MoE = z \cdot (\frac{\sigma}{\sqrt{n} } ) $\\\\](https://tex.z-dn.net/?f=%24%20MoE%20%3D%20z%20%5Ccdot%20%28%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%29%20%20%24%5C%5C%5C%5C)
Re-arranging for the sample size (n)
![$ n = (\frac{z \cdot \sigma }{MoE})^{2} $](https://tex.z-dn.net/?f=%24%20n%20%3D%20%28%5Cfrac%7Bz%20%5Ccdot%20%5Csigma%20%7D%7BMoE%7D%29%5E%7B2%7D%20%20%24)
Where z is the value of z-score corresponding to the 98% confidence level.
Since we want mean salary to be within $2,000, therefore, the margin of error is 2,000.
The z-score for a 98% confidence level is 2.326
So the required sample size is
![n = (\frac{2.326 \cdot 10,500 }{2,000})^{2}\\\\n = (12.212)^{2}\\\\n = 149.13\\\\n = 150](https://tex.z-dn.net/?f=n%20%3D%20%28%5Cfrac%7B2.326%20%5Ccdot%2010%2C500%20%7D%7B2%2C000%7D%29%5E%7B2%7D%5C%5C%5C%5Cn%20%3D%20%2812.212%29%5E%7B2%7D%5C%5C%5C%5Cn%20%3D%20149.13%5C%5C%5C%5Cn%20%3D%20150)
Therefore, we need to take a sample size of at least 150 state employees to estimate with 98% confidence the mean salary to be within $2,000.
First you would need to combine like terms. do you know how to do that?