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Pavel [41]
3 years ago
6

If a=0 b=0 then complex number a+bi is what type NEED HELP THANKS

Mathematics
2 answers:
notka56 [123]3 years ago
5 0
The answer is a. If there is an i in the equation, then that means “i” is imaginary.
Savatey [412]3 years ago
5 0

Answer:

imaginary

Step-by-step explanation:

b ≠ 0 and a = 0

a + i b  ===> a -> real and b i is imaginary

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A car travels 240 kilometers in 2 1/2 hours what is its speed
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Graph the system &amp; write its solution <br> 2x+y=-4<br> Y=-1/2x-1
xz_007 [3.2K]

Answer:

The solution of system of equation is (-2,0)

Step-by-step explanation:

Given system of equation are

Equation 1 :      2x+y=(-4)

Equation 2 :      y+\frac{1}{2}x=(-1)

To plot the equation of line, we need at least two points

For Equation 1 : 2x+y=(-4)

Let x=0

2x+y=(-4)

2(0)+y=(-4)

y=(-4)

Let x=1

2x+y=(-4)

2(1)+y=(-4)

y=(-6)

Therefore,

The required points for equation is (0,-4) and (1,-6)

For Equation 2 : y+\frac{1}{2}x=(-1)

Let x=0

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(0)=(-1)

y=(-1)

Let x=2

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(2)=(-1)

y=(-2)

The required points for equation is (0,-1) and (2,-2)

Now, plot the graph using this points

From the graph,

The red line is equation 1 and blue line is equation 2

Since. The point of intersection is solution of system of equations

The solution of system of equation is (-2,0)

6 0
3 years ago
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