Answer:
Option 1) p ←→ q
Step-by-step explanation:
The given statement is a combination of two phrases with a connective word.
Phrase 1 - The Fratellis will be arrested.
We consider this phrase as phrase p.
Phrase 2 - If the police believe chunk.
Phrase q.
Now these statements p and q are connected with a connecting word "If only and only".
When two phrases are connected by the connecting words "Only and only if", this connecting word is called as biconditional operator.
p (connecting word) q
p ( If and only if) q
p ←→ q
Therefore, Option 1) p ←→ q is the answer.
Answer:
Step-by-step explanation:
With each iteration, you're swapping the two coordinates, and then change sign of the first one:
First transformation
- Start with (3,1)
- Swap coordinates: (1,3)
- Change sign of the first coordinate: (-1,3)
Second transformation
- Start with (-1,3)
- Swap coordinates: (3,-1)
- Change sign of the first coordinate: (-3,-1)
Third transformation
- Start with (-3,-1)
- Swap coordinates: (-1,-3)
- Change sign of the first coordinate: (1,-3)
The function, as presented here, is ambiguous in terms of what's being deivded by what. For the sake of example, I will assume that you meant
3x+5a
<span> f(x)= ------------
</span> x^2-a^2
You are saying that the derivative of this function is 0 when x=12. Let's differentiate f(x) with respect to x and then let x = 12:
(x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
[x^2-a^2]^2
(144-a^2)(3) - (36+5a)(24)
------------------------------------ = 0
[ ]^2
Simplifying,
(144-a^2) - 8(36+5a) = 0
144 - a^2 - 288 - 40a = 0
This can be rewritten as a quadratic in standard form:
-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.
Solve for a by completing the square:
a^2 + 40a + 20^2 - 20^2 + 144 = 0
(a+20)^2 = 400 - 144 = 156
Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)
Finally, a = -20 plus or minus 2sqrt(39)
You must check both answers by subst. into the original equation. Only if the result(s) is(are) true is your solution (value of a) correct.
