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Licemer1 [7]
3 years ago
15

PLEASE HELP PLEASE PLEASE HELP

Mathematics
1 answer:
dexar [7]3 years ago
6 0

Let's consider the choices:

⊕ same y-intercept: f(0) = -4; g(0) is undefined. NO

⊕ always positive: f(0) = -4. NO

⊕ decreasing when x > 2; f(x) has slope -1/2; g(x) has slope -2. YES

⊕ same value for x=-2; f(-2) = 0; g(-2) is undefined. NO

The appropriate choice is the 3rd one ...

... Both functions are decreasing for values of x > 2.

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Mr. Sanchez’s class sold fruit pies for $1.55 each and Mr. Kelly’s class sold bottles of fruit juice for $1.40 each. Together, t
hoa [83]

Answer:

Mr. Sanchez's class sold 28 fruit pies and Mr. Kelly's class sold 32 bottles of fruit juice.

Step-by-step explanation:

Let x be the number of fruit pies sold and y be the number of bottles of fruit juice sold.

Together, the classes sold 60 items, so

x + y = 60

Mr. Sanchez’s class sold fruit pies for $1.55 each, so x fruit pies cost $1.55x.

Mr. Kelly’s class sold bottles of fruit juice for $1.40 each, so y bottles of fruit juice cost $1.40y.

Together, the classes  earned $88.20 for their school, so

1.55x + 1.40y = 88.20.

You get the system of two equations:

\left\{\begin{array}{l}x+y=60\\ \\1.55x+1.40y=88.20\end{array}\right.

From the first equation:

x=60-y

Substitute it into the second equation:

1.55(60-y)+1.40y=88.20\\ \\93-1.55y+1.4y=88.2\\ \\-0.15y=88.2-93\\ \\-0.15y=-4.8\\ \\0.15y=4.8\\ \\15y=480\\ \\y=32\\ \\x=60-32=28

Mr. Sanchez's class sold 28 fruit pies and Mr. Kelly's class sold 32 bottles of fruit juice.

8 0
3 years ago
lilli has $3.65 comprised of quarters and dimes floating on the bottom of her bag she has five more dimes than twice her quarter
marta [7]

Answer:

= 3.65.

Step-by-step explanation:

You know that Tom has 23 coins in total. That means the number of dimes and the number of quarters equals 23.

D + Q = 23

You also know that the total value of the coins is $3.65. A dime is worth $0.10 and a quarter is worth $0.25, so:

0.10*D + 0.25*Q = 3.65

That says that 10 cents per dime times the number of dimes, plus 25 cents per quarter times the number of quarters is three dollars and sixty-five cents.

So you have a system of linear equations:

D + Q = 23

0.10D + 0.25Q = 3.65

I'm going to multiply the bottom row by 100 to clear the decimals.

D + Q = 23

10D + 25Q = 365

Now I can multiply the top row by -10 to eliminate the D terms

-10D - 10Q = -230

10D + 25Q = 365

________________

0D + 15Q = 135

15Q = 135

Q = 9

Tom has 9 quarters.

If D + Q = 23, and Q = 9, then:

D + 9 = 23

D = 14

Tom has 14 dimes.

Always good to double check:

9 quarters is worth $2.25. 14 dimes is worth $1.40. These should sum to $3.65.

2.25 + 1.40

8 0
3 years ago
Find the products.please please please please please help me! I’m desperate!
Dmitry_Shevchenko [17]

Answers:

5) product is 35ax^2 - 42axy + 7y^2

6) product is -a^6b^2 - 8a^5b - 5a^4

7) product is 12x^5y + 6x^4y^2 + 21x^3y^3

8) product is 3x^3y^2 - 6x^3y + 3x^5y - 3x^4y

9) product is x^{3n} + 7x^{n+1} - 3x^n

=============================================

Explanation:

For each of these questions, you'll multiply the term outside by each term inside the parenthesis. I'm using the distributive property.

In problem 5, we multiply the outer 7a by the following terms inside like so

7a(5x^2-2xy+y^2-4xy)\\\\7a(5x^2-6xy+y^2)\\\\7a(5x^2)+7a(-6xy)+7a(y^2)\\\\35ax^2-42axy+7ay^2\\\\

The other problems will have similar steps.

--------

A useful rule to keep in mind is that a^b*a^c = a^{b+c}

For example, x^2*x^3 = x^{2+3} = x^5

3 0
2 years ago
Which ratio is greater 8/15 or 5/9​
elena-14-01-66 [18.8K]

Answer:

5/9

Step-by-step explanation: If you find a common denominator ( i found 135 ) and you multiply each numerator by the number u multiplied the denominator to get the common denominator, you can see that 5/9 is greater. hope this helps and sorry if that was confusing

5 0
3 years ago
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Avenue A is perpendicular to North Street. What is the relationship between Avenue A and South Street?
MAVERICK [17]
I need more information
6 0
3 years ago
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