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Crank
3 years ago
10

I'm sorry but I do not get the question here. I need help.

Mathematics
2 answers:
Roman55 [17]3 years ago
6 0

Answer:

wider and open downward

Nitella [24]3 years ago
5 0

Answer:

narrower and open upward

Step-by-step explanation:

multiplying a by 2 is stretching the graph vertically by a factor of two. essentially this pulls the graph upward, making the graph narrower. Imagine pulling on a rubber band. As you stretch it upwards, it gets taller, but it also gets narrower. This is also true of the parabola. You also know the parabola opens upwards because the equation is positive, and all positive parabola equations open upwards.

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Q
katrin2010 [14]

Answer:

v= -(-v)

Step-by-step explanation:

3 0
2 years ago
Y=x +3<br>1 23x+2y=-4<br>what is it ​
erik [133]

Answer:

x=-0.08 and y=2.92

Step-by-step explanation:

123x + 2(x+3) = -4             y = -0.08 + 3

123x + 2x + 6 = -4                = 2.92

125x + 6 = -4

125x = -10

x= -0.08

5 0
2 years ago
Solve the following inequality algebraically. -5|1 - 2x| + 6 =&lt; -29​
Blababa [14]

Answer:

x<3

Step-by-step explanation:

-5|1+2x|+6<-29

-5-10x+6<-29

-10x<-30

-----    ----

-10     -10

x<3

8 0
3 years ago
NEED HELP!
Citrus2011 [14]

Answer:

Michelle, because she was only 5 off, while Jae was 8 off

8 0
2 years ago
A B R and P are four points on a circle with centre 0. A O R and C are four points on a different circle. The two circles inters
Slav-nsk [51]

Answer:

x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)

Step-by-step explanation:

APRB form a cyclic trapezoid

∠APO  = x° (Base angle of an isosceles triangle)

∠OPR  = ∠ORP (Base angle of an isosceles triangle)

∠ORB = ∠OBR (Base angle of an isosceles triangle)

∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)

Similarly;

∠ORB + ∠ORP + x°  = 180°

Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR  = ∠ORP we put

We also have;

∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)

Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR

Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.

6 0
3 years ago
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