I'm sorry but I do not get the question here. I need help.

Mathematics

2 answers:

Roman55 [17]3 years ago

6 0

Answer:

wider and open downward

Nitella [24]3 years ago

5 0

Answer:

narrower and open upward

Step-by-step explanation:

multiplying a by 2 is stretching the graph vertically by a factor of two. essentially this pulls the graph upward, making the graph narrower. Imagine pulling on a rubber band. As you stretch it upwards, it gets taller, but it also gets narrower. This is also true of the parabola. You also know the parabola opens upwards because the equation is positive, and all positive parabola equations open upwards.

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Given qr = 4.8, m angle r space equals space 80 degree , and m angle p equals 42 degree ... if you want to find pq.... a. should

Lady bird [3.3K]

By applying the law of sines, the length of side PQ is equal to 7.1 units.

<h3>What is the law of sines?</h3>

The law of sines is also referred to as sine law and it can be defined as an equation that relates the side lengths of a triangle to the sines of its angles.

<h3>How to calculate the length of PQ?</h3>

Mathematically, the law of sines is given by this equation:

$\frac{sinA}{a} =\frac{sinB}{b} =\frac{sinC}{c}$

Substituting the given parameters into the formula, we have;

$\frac{sin80}{PQ} =\frac{sin42}{4.8} \\\\\frac{0.9848}{PQ} =\frac{0.6691}{4.8}\\\\0.6691PQ = 4.7270\\\\PQ = 4.7270/0.6691$

PQ = 7.1 units.

Read more on law of sines here: brainly.com/question/7922954

#SPJ1

4 0

2 years ago

Consider the expression. (StartFraction 2 m Superscript negative 1 baseline n Superscript 5 Baseline Over 3 m Superscript 0 Base

suter [353]

Answer:

The correct option is option (3) 4 ÷ 25.

Step-by-step explanation:

The expression in terms of <em>m</em> and <em>n</em> is:

$F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}$

Exponent rule of division:

$a^{x}\div a^{y}=a^{x-y}$

Compute the value of the expression for <em>m</em> = -5 and <em>n</em> = 3 as follows:

$F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}$

$F(-5,3)=[\frac{2\csdot (-5)^{-1}\cdot (3)^{5}}{3\cdot (-5)^{0}\cdot (3)^{4}}]^{2}$

$=\{\frac{2}{3}\times [(-5)^{-1-0}\times (3)^{5-4}}]\}^{2}\\\\=\{\frac{2}{3}\times \frac{-1}{5}\times 3\}^{2}\\\\=\{-\frac{2}{5}\}^{2}\\\\=\frac{4}{25}$