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Pavlova-9 [17]
3 years ago
11

Describe the difference between total surface area and lateral surface area

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

The total surface area of a solid is the sum of the areas of all of the faces or surfaces that enclose the solid, the lateral surface area of a solid is the surface area of the solid without the bases

OLga [1]3 years ago
3 0

Answer:

The lateral surface of an object is the area of all the faces of the object, excluding the area of its base and top. For a cube, the lateral surface area would be the area of four sides. Total Surface Area (TSA) Total surface area is the area of all the faces including the bases.

Step-by-step explanation:

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What is the lowest common denominator of 20 and 24
Debora [2.8K]
The lowest common denomenator is the smallest common factor of them so
20=1 times 2 times 2 times 5
24=1 times 2 times 2 times 2 times 3
the lowest common denomenator is 1


I think the question should have been. what is the greatest common factor (4) or what is the smallest common multiple (120)
6 0
3 years ago
What is the P(Red Diamond Face Card) and the P (Black Face Card) ​
levacccp [35]

Answer:

9/1352.

Step-by-step explanation:

P(Red Diamond Face Card) = 3/52.

P (Black Face Card) = 6/52 = 3/26.

So the answer is 3/52 * 3/26

= 9/1352.

4 0
2 years ago
Clean123 Inc. is preparing its balance sheet. It has $59,000 in accounts receivable, $32,000 in accounts payable, $41,000 in not
MrMuchimi

Answer:

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3 0
3 years ago
A basket of fruit contains 4 bananas, 3 apples, and 5 oranges. You intend to draw a piece of fruit from the basket, keep it, dra
gregori [183]

Answer:

The probability that the fruits will be selected in the order of banana then apple then orange is 0.1094

Step-by-step explanation:

The given information are;

The number of bananas = 4

The number of apples = 3

The number of oranges = 5

The total number of fruits are 4 + 3 + 5 = 12

The probability of selecting a banana, p(b) = 4/12 = 1/3

The probability of selecting an apple, p(a) = 3/12 = 1/4

The probability of selecting an oranges, p(o) = 5/12

The probability of selecting one banana, then one apple, then one orange, in that order, from the basket with replacement is the product of the individual probabilities found as follows;

p(p(b) then p(a) then p(o)) =

The number o

The probability that the first fruit is a banana = ₁₁C₃×(1/3)^(3)×(2/3)^8 = 0.2384

The probability that the second fruit is an apple = ₁₁C₃×(1/4)^(3)×(3/4)^8 = 0.258

The probability that the third fruit is an apple = ₁₁C₃×(5/12)^(3)×(7/12)^8 = 0.16

The total probability = 0.2384 + 0.285 + 0.16 = 0.657

The number of ways in which the three can be selected = 3 × 2 × 1 = 6 ways

Therefore, the probability that the fruits will be selected in the order of banana then apple then orange = 0.657/6 = 0.1094.

4 0
3 years ago
8 of 10
Naya [18.7K]

Answer:

2.

Step-by-step explanation:

To find the answer, we take Gordon's result, 3, and subtract 2, which is what he added to get 3. This gives us a result of 1. We then multiply by 2, as 1 was the quotient of dividing the original number by 2. This leaves us with an answer of 2.

7 0
3 years ago
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