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Papessa [141]
3 years ago
9

(4 x 10") + (2 x 10) =

Mathematics
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

60

Step-by-step explanation:

40+ 20

60

this is your answer

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Can u help me solve this pls
lisov135 [29]
Answer:

First option: (Substitute)

2x+3 (x+1.5) = 12
3 0
2 years ago
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Solve the following equation when x = 7. y = 8 + 3x <br> HELP
Grace [21]

Answer:

y=29

Step-by-step explanation:

Replace x with 7:

y=8+3(7)

Multiply 7 and 3:

y=8+21

Add together:

y=29

4 0
3 years ago
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If f(x)=2x^2sqrt(x-2), complete the following statement f(6)
Sergio [31]
Hello : 
f(6) =2(6)² +<span>√(6-2) = 72 +2 =74</span>
8 0
3 years ago
Can anyone fill these out?
Tcecarenko [31]

Answer:

Part (a)

36

Part (b)

Find the filled table in the attachment

Part (c)

1/36

Step-by-step explanation:

The total number of possible outcomes using the multiplicative rule is given by;

6*6 = 36.

There are 6 possible outcomes in rolling each die, we simply find the product.

The probability of rolling double sixes is given by;

pr(6 and 6) = pr(6) * pr(6) = 1/6 * 1/6 = 1/36

The probability of rolling double sixes represents independent events and thus we employ the multiplicative rule of probability.

8 0
3 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
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