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tia_tia [17]
3 years ago
5

What is the range of the function f(x) = |x| – 3?

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

9514 1404 393

Answer:

  all real numbers greater than or equal to –3

Step-by-step explanation:

|x| has a range of all real numbers greater than or equal to zero, so f(x) = |x|-3 will have a range of ...

  all real numbers greater than or equal to -3

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He would have to work 13 hours

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A relative asked her aunt that lives in a certain part of the US to send her some money for food expenses in Canada. Her aunt se
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3 years ago
What 1 thruogh 100 added up them divided
Marina CMI [18]
We can use the sum of an aritmetic sequence
the sum from n=1 to n=r when the first term is a1 and the nth term is an is
S=\frac{n(a_1+a_n)}{2}
first term is 1
last term is 100
there are 100 terms so n=100

so the sum is S=\frac{100(1+100)}{2}
S=(50)(101)
S=5050
now you want us to divide by 10
5050/10=505


fun fact, gauss (famous math guy) did this when he was younger, legend has it that he was assigned this as an in class assigment to kill time but gauss found a neat pattern, he noticed that adding the end terms wer giving the same sum, example, 100+1=101, 2+99=101, etc, so he just needed to find al the pairs and add them all up




answer is 505
the result is 505
5 0
3 years ago
Which best describes the incenter of a triangle?
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The correct answer of the given question above about the incenter of a triangle is option B. The statement that best describes the incenter of a triangle is that, it is the point where the three angle bisectors of the triangle intersect. In geometry, an incenter of a triangle is described as the triangle center. 
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3 years ago
Read 2 more answers
Please help me as soon as posable!! In hurry!!(24 points)
attashe74 [19]

The sequence is geometric, so

a_n = r a_{n-1}

for some constant r. From this rule, it follows that

a_3 = r a_2 \implies 20 = 2r \implies r = 10

and we can determine the first term to be

a_2 = r a_1 \implies 2 = 10 a_1 \implies a_1 = \dfrac15

Now, by substitution we have

a_n = r a_{n-1} = r^2 a_{n-2} = r^3 a_{n-3} = \cdots

and so on down to (D)

a_n = r^{n-1} a_1 = 10^{n-1} \cdot \dfrac15

(notice how the exponent on r and the subscript on a add up to n)

4 0
2 years ago
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