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2 years ago

Complete the statement to describe the expression abc + def

Mathematics

1 answer:

laila [671]2 years ago

4 0

Answer:

What statement?

abc + def = def+ abc??

Step-by-step explanation:

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Change 3 to 5 in exercise 4

Nonamiya [84]

So 5 4 3 I think yeah

5 0

2 years ago

(01.02 LC) Simplify 8 - (14)

nignag [31]

Answer:

8-14 or -6

Step-by-step explanation:

7 0

3 years ago

Please solve quickly

Sloan [31]

The degenerate conic that is formed when a double cone is sliced at the ap-ex by a plane parallel to the base of the cone is a <u>Point</u>.

<h3>What degenerate conic is formed?</h3>

When a plane that is parallel to the base of a double cone is used to slice the ap-ex, the conic section formed is a circle.

Circles lead to a Point degenerate conic being formed because a single point will be formed on the double cone that separates the shape.

Find out more on degenerate conics at brainly.com/question/14276568

#SPJ1

8 0

1 year ago

Help its geometry...............

Digiron [165]

m GH = 57''

________

tan 39° = opposite / adjacent

tan 39° = m GH / m HJ

tan 39° * m HJ = m GH

m HJ = m GH / tan 39°

m HJ ≈ 57'' / 0.810

m HJ ≈ 70.4'' <——<span>— measure of the segment HJ</span>

________

sin 39° = opposite / hypotenuse

sin 39° = m GH / m GJ

sin 39° * m GJ = m GH

m GJ = m GH / sin 39°

m GJ = 57'' / 0.629

m GJ ≈ 90.6'' <——— measure of the segment GJ

________

So the perimeter is

p = m GH + m HJ + m GJ

p = 57'' + 70.4'' + 90.6''

p = 218'' <——<span>— this is the answer.</span>

I hope this helps. =)

Tags: <em>perimeter right triangle sine cosine tangent sin cos tan trig trigonometry geometry</em>

7 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago