What is the inequality for -8x>48

The product of two rational numbers is 34.77. If one of the numbers is 6.1, what is the other number?

erik [133]

Answer:

5.7

Step-by-step explanation:

6 0

3 years ago

A box contains 2 red marbles , 3 green marbles , and 3 blue marbles

krek1111 [17]

Answer:

the box contains a total of 8 marbles .

although if you understand pixels then you would know that could stand for RGB so your color would be a very dark greenish brown

Step-by-step explanation:

no question?

5 0

3 years ago

Anne wants to fill 12 hanging baskets with compost. Each hanging basket is a hemisphere of diameter 40 cm.

murzikaleks [220]

Answer:

no

Step-by-step explanation:

Steps to answering this question

determine the volume of the 12 basket

volume of a hemisphere = (2/3)πr^3

n = 22/7

r = radius

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

radius = 40/2 = 20 cm

volume of one hemisphere = (2/3) x (22/7) x (20^3) = 16,761.90 cm^3

volume of the 12 baskets = 16,761.90 cm^3 x 12 = 201,142.86 cm^

2. convert the litres of compost to cm and multiply by the total bags of compost

1 litre = 1000cm

1 bag of compost = 50 x 1000 = 50,000

4 bags of compost = 50,000 x 4 = 200,000 cm

3. compare which figure is higher. the figure gotten in step 1 or 2

201,142.86 cm^3 is greater than 200,000

there is no enough compost

473691.4

273691.4

3 0

3 years ago

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .