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Lina20 [59]
2 years ago
9

Two lizards with long tails have 4 offspring. All the offspring have long tails. What does this tell you about the tail genes th

at the offspring received?
Biology
2 answers:
Paha777 [63]2 years ago
8 0
The long tailed gene is dominant
Ivahew [28]2 years ago
6 0
That the long tailed gene is not a recessive trait
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A new human species was found on a distant planet, whose genetic inheritance and process of reproduction is identical to that of
Vedmedyk [2.9K]

Answer:

  1. E/e ; T/t  ⇒ Square eyes and long tail (Option D)
  2. 3/16 will have round eyes and long tails (Option C)
  3. 1/4 of the progeny will be heterozygous for both traits (Option A)

Explanation:

<u>Available data</u>:

  • Two diallelic unlinked genes
  • Gene E controls eye shape: Dominant allele E expresses square eyes, and recessive allele e expresses round eyes.
  • Gene T controls the tail size. Dominant allele T expresses long trail, and recessive allele t expresses short tail.

<u>Genotypes                                          Phenotypes</u>

EETT, EeTT, EETt, EeTt                     Square eyes and Long tail

eeTT, eeTt                                          Round eyes and Long tail

EEtt, Eett                                             Square eyes and Short tail

eett                                                      Rounf eyes and short tail.

<em>1. An individual of this new species is heterozygous for gene E and heterozygous for gene T. What is their genotype and phenotype?</em>

The heterozygous individual is E/e ; T/t, expressing square eyes and a long tail.

<em>2. Two individuals, who are both heterozygous for eye shape and tail size, mate. Which of the following is a correct statement about the phenotype ratios expected for their offspring?</em>

Cross: between two heterozygous individuals

Parentals) EeTt    x     EeTt

Gametes) ET, Et, eT, et

                ET, Et, eT, et

Punnett square)  .   ET        Et        eT       et

                  ET     EETT    EETt    EeTT    EeTt

                  Et      EETt     EEtt     EeTt      Eett

                  eT    EeTT    EeTt    eeTT     eeTt

                   et     EeTt      Eett     eeTt      eett

F1) Genotype:

  • 1/16 EETT
  • 2/16 EETt
  • 1/16 EEtt
  • 2/16 EeTT
  • 4/16 EeTt ⇒ 1/4 EeTt
  • 2/16 Eett
  • 1/16 eeTT
  • 2/16 eeTt
  • 1/16 eett

      Phenotype

  • 9/16 E-T-, Square eyes and Long tails
  • 3/16 E-tt, Square eyes and short tails
  • 3/16 eeT-, Round eyes and Long tails
  • 1/16 eett, round eyes and short tail

Phenotypic ratio 9:3:3:1

<em>3. From the mating described in question ABOVE, what proportion of ALL of the offspring in will be heterozygous for both traits?</em>

4/16 = 1/4 = 25% of the progeny are expected to be heterozygous for both traits, EeTt.

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Consider a gene that exists in two allelic forms in a simple Mendelian dominant/recessive pair. In a large population of randoml
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Answer: Option a) the frequency of the homozygous dominants will go down, the frequency of the heterozygous genotype will go down, and the frequency of the homozygous recessives will go up

Explanation: Another name for gene frequency is the allele frequency. It is the percentage of any chromosomes in the population that contains that particular gene or allele. It also shows the genetic diversity that can present in a species.

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