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ANTONII [103]
3 years ago
6

Which of the following inequalities has a solution x≥−3?(1 point)

Mathematics
1 answer:
andre [41]3 years ago
6 0
The answer would be B
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Dave bought 1.2 pounds of plums for $0.50 per pound he also bought 1.5 pounds of nuts for $2.50 per pound Dave gave the cashier
andre [41]

Answer:

$5.65

Step-by-step explanation:

1.20x0.50=0.60
1.50x2.50=3.75
0.60+3.75=4.35
10.00-4.35
5.65

5 0
3 years ago
Read 2 more answers
1. What is the place value of the 1 in 1,234,567,890? ​
FrozenT [24]

Answer:

The place value of 1 in 1,234,567,890 is <u>1</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>.</u>

4 0
2 years ago
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Alan, Bianca, and Charles are counting in turn. Alan says "one," Bianca says "two," and Charles says "three." Then it's Alan's t
timama [110]
Bianca would say fifty nine
8 0
3 years ago
Given f(x)<br> 6x – 5<br> a) Evaluate f(5)<br> f(5)<br> b) Evaluate f( - 3)<br> f(-3) =
prisoha [69]
We have the equation f(x)=6x-5 to start with
Now in order to answer the question we have to know that f(5) is the same thing as setting x=5 and solving for f(5)

(A) f(5) = 6(5) - 5 = 30 - 5 = 25
(B) f(-3) = 6(-3) - 5 = (-18) - 5 = -23

So f(5) = 25 and f(-3) = -23
8 0
3 years ago
If p+1/p - 7 then find the value of p³+1/p³ ​
ankoles [38]

Answer:

322

Step-by-step explanation:

We have,

a^3+b^3=(a+b)^3-3ab(a+b)

p+1/p=7

Now,

p^3+1/p^3=(p+1/p)^3-3*p*1/p(p+1/p)

               =7^3-3(7)=343-21=322

5 0
3 years ago
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