5 : 25 → (÷5) → 1 : 5
Answer : 1 : 5
The lengths of HJ and JK are 50 and 72 respectively.
Given: J is between H and K. the length of HJ=2x+4, JK=3x+3, and HK=22.
The line HJ and JK are collinear then the total length is given as: HJ+JK=HK
substitute values
⇒ (2x+4)+(3x+3)=22
⇒ 5x+7=22
⇒ 5x=22-7
⇒ 5x=15
⇒ x=3
Thus, the length of HJ is (2x+4)=(2*3+4)=10
And the length of JK is (3x+3)=(3*3+3)=12
Learn more about collinear lines here: brainly.com/question/27943430
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Answer:
35
Step-by-step explanation:
Answer:
87.92 in²
Step-by-step explanation:
pi × (R² - r²) = area
Where R is the radius of the outer circle and r of the inner circle.
Since C = 2pi×r
37.68 = 2×3.14×r
r = 6 in
R = 6 + 2 = 8 in
Therefore,
pi × (R² - r²) = area
Area = 3.14 (8² - 6²)
= 87.92 in²
B. Junichi's garden is wider than 50 ft.
