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qwelly [4]
3 years ago
6

The perimeter of AABC is 30 feet AB = 5x - 7, BC = 3x + 1, AC = 4x. List the angles of AABC in order from smallest to largest

Mathematics
1 answer:
Monica [59]3 years ago
8 0
What? Itjdocnwncie idodiwjdodjws
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Help on this question ASAP PLEASE!!!
serious [3.7K]
X=4 is the answer if you are looking for x

4 0
3 years ago
Plz help I don’t get it
vlabodo [156]

Answer:

[4, positive infinity)

Step-by-step explanation:

since there is a closed circle on 4, we include 4 in the continuous interval, and we assume that the arrow represents continuity after the graph ends, so the interval of continuity is from 4 to positive infinity.

5 0
3 years ago
Is |4x+2|+6=0 no solution, all real numbers, 0, and 2
algol [13]

                                        <u>|4x + 2| + 6 = 0</u>

Subtract  6  from each side:  |4x + 2| = -6

But the absolute value of a number is always positive.
No value of 'x' can ever make  |4x + 2|  negative.

So the equation has <em>no solution</em>.


7 0
3 years ago
Provide a real life algebra situation that has one solution (i.e. 3x = 6)
Sholpan [36]
3(x)=6
3(2)=6
which says 6=6
7 0
3 years ago
I’m stuck can some one help me
abruzzese [7]

Answer:

3) Midpoint is (-4,0.5)

Option A is correct.

4) Midpoint is (2.5,0)

Option B is correct.

5) The factors are (x+4)(x-7)

Option C is correct.

6) The factors are (x+4)(x+2)

Option A is correct.

Step-by-step explanation:

Question 3

Find midpoint of the following:

(2,-7), (-10,8)

The formula used to find midpoint is: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

We have x_1=2, y_1=-7, x_2=-10,y_2=8

Putting values and finding midpoint

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2-10}{2},\frac{-7+8}{2} )\\Midpoint=(\frac{-8}{2},\frac{1}{2} )\\Midpoint=(-4,0.5 )

So, Midpoint is (-4,0.5)

Option A is correct.

Question 4

Find midpoint of the following:

(2,-10), (3,10)

The formula used to find midpoint is: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

We have x_1=2, y_1=-10, x_2=3,y_2=10

Putting values and finding midpoint

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2+3}{2},\frac{-10+10}{2} )\\Midpoint=(\frac{5}{2},\frac{0}{2} )\\Midpoint=(2.5,0 )

So, Midpoint is (2.5,0)

Option B is correct.

Question 5

Factor each completely

x^2-3x-28

We will break the middle term and find factors

x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)

So, the factors are (x+4)(x-7)

Option C is correct.

Question 6

Factor each completely

x^2+6x+8

We will break the middle term and find factors

x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)

So, the factors are (x+4)(x+2)

Option A is correct.

7 0
2 years ago
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