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Setler [38]
3 years ago
13

Peter, Jan, and Maxim are classmates. Their total score for the last test was 269. Peter's score was more than the sum of Jan's

and Maxim's scores. What could be Peter's least possible score?
Mathematics
1 answer:
Goshia [24]3 years ago
5 0

Answer:

135

Step-by-step explanation:

Given that :

Total score obtained by Peter, Jan and Maxim = 269

Let :

Peter's score = x

Jan's score = y

Maxim's score = z

x + y + z = 269

x > (y + z)

For x to be greater Than y + z ;

Then x > (269 / 2) ; x > 134.5

The least possible x score is 135

Hence, Peter's least possible score is 135.

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In Need of help please Help :c
Oksanka [162]

Answer:

  • proportional: A, B, D, G, I
  • non-proportional: C, E, F, H

Step-by-step explanation:

Any relation with a non-zero initial value or y-intercept is non-proportional. Any relation that has a constant ratio between output and input is proportional.

  C has an initial value of 7

  E has a y-intercept of -3

  F has an initial value of 2.00

  H has an initial value of 5

All of these are non-proportional. The remainder are proportional.

3 0
2 years ago
Stephen Curry's record during the 2017 - 2018 NBA final game is made up of 2-point shots and 3-points.
grandymaker [24]

Answer:

x =  12      ( two points shots )

y =  7       ( three points shots )

Step-by-step explanation:

Let´s call  "x" two points shots,  and  "y" three points shots, then

x  +  y  =  19

2*x  +  3*y  =  45

We have to solve a two-equation system for x and y

y =  19  - x

2*x  +  3 * ( 19 - x ) = 45

2*x  +  57  -  3*x   =  45

- x   =  45 - 57

-x   =  - 12

x  = 12

And     y  =  19  -  12

y  = 7

4 0
3 years ago
A veterinary clinic saw 45 pets on Monday. The shaded squares in the grid below represent the 60% of pets
Black_prince [1.1K]
Answer: 27 dogs were seen at the clinic on monday.

27/45 = 0.6

0.6 = 60%
3 0
2 years ago
Read 2 more answers
PLEASE HELP.
krek1111 [17]

Answer:

Part a) The radii are segments AC and AD and the tangents are the segments CE and DE

Part b) DE=4\sqrt{10}\ cm

Step-by-step explanation:

Part a)

we know that

A <u>radius</u> is a line from any point on the circumference to the center of the circle

A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.

In this problem

The radii are the segments AC and AD

The tangents are the segments CE and DE

Part b)

we know that

radius AC is perpendicular to the tangent CE

radius AD is perpendicular to the tangent DE

CE=DE

Triangle ACE is congruent with triangle ADE

Applying the Pythagoras Theorem

AE^{2}=AC^{2}+CE^{2}

substitute the values and solve for CE

14^{2}=6^{2}+CE^{2}

CE^{2}=14^{2}-6^{2}

CE^{2}=160

CE=\sqrt{160}\ cm

CE=4\sqrt{10}\ cm

remember that

CE=DE

so

DE=4\sqrt{10}\ cm

7 0
3 years ago
I need help and I’m like really confused lol❤️
grandymaker [24]

If I did this right it should be 8.

8 0
3 years ago
Read 2 more answers
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