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gtnhenbr [62]
3 years ago
15

Solve 4/√7-1 +2/√7+1

Mathematics
2 answers:
vekshin13 years ago
7 0

Answer:

<h3>\frac{4}{\sqrt{7}}-1+\frac{2}{\sqrt{7}}+1</h3>

=\frac{4}{\sqrt{7}}+\frac{2}{\sqrt{7}}-1+1

\frac{4}{\sqrt{7}}+\frac{2}{\sqrt{7}}=\frac{6\sqrt{7}}{7}

\frac{6\sqrt{7}}{7}-1+1

-1+1=0

=\frac{6\sqrt{7}}{7}

<u>OAmalOHopeO</u>

Goshia [24]3 years ago
5 0

Answer:

Answer is (6\sqrt{7} +2)/6

Step-by-step explanation:

The question isn't very clear, so I'm gonna assume the denominator is  \sqrt{7}-1 and \sqrt{7}+1

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Step-by-step explanation:


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Write the set of real numbers from - 10 through 10 in interval notation.
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3) [-10, 10) - Greater than or equal to -10 and less than 10.

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Step-by-step explanation:

There are four form of describing that set in interval notation, which presented below:

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2) [-10, 10] - Greater than or equal to -10 and less than or equal to 10.

3) [-10, 10) - Greater than or equal to -10 and less than 10.

4) (-10, 10] Greater than -10 and less than or equal to 10.

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Answer:

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