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kipiarov [429]
3 years ago
7

What is the solution set for this inequality

Mathematics
2 answers:
Alexus [3.1K]3 years ago
6 0

Answer:

x

Step-by-step explanation:

-8x+40>-16

Move the <u>constant</u> to the right-hand side and change its sign

-8x>-16-40

Calculate the difference

-8x>-56

Divide both sides of the inequality by -8 and flip the inequality sign

x < 7

Therefore the Correct Answer B. <u>x < 7</u>

kompoz [17]3 years ago
5 0

Answer:

x  <  7

Step-by-step explanation:

1) Subtract 40 from both sides.

- 8x >  - 16 - 40

2) Simplify -16 - 40 to -56.

- 8x >  - 56

3) Divide both sides by -8.

x >  \frac{ - 56}{ - 8}

4) Two negative numbers makes a positive.

x >  \frac{56}{8}

5) Simplify 56/8 to to 7.

x < 7

<em><u>Therefor</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>option</u></em><em><u> </u></em><em><u>B</u></em><em><u>.</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u><</u></em><em><u> </u></em><em><u>7</u></em><em><u>.</u></em>

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Step-by-step explanation:

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Answer:

-3

Step-by-step explanation:

27 divided by 9 is 3

the signs (+) / (-) = -

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kodGreya [7K]
<h3><u>Fraction to Decimal:</u></h3>

Divide the numerator (upper number) by the denominator (bottom number) on your calculator. Whatever number you get would be your decimal.

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Take your decimal and use your calculator to multiply it by 100. Whatever number you get would be your percent. However, since it is a percent, you need to include the percentage unit.

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7 0
4 years ago
Bastien, Inc. has been manufacturing small automobiles that have averaged 50 miles per gallon of gasoline in highway driving. Th
alexira [117]

Answer:

We conclude that the the manufacturer's advertising campaign is not correct.

P-value of test = 0.067.

Step-by-step explanation:

We are given that an independent testing service road-tested 36 of the automobiles. The sample showed an average of 51.5 miles per gallon. The population standard deviation is 6 miles per gallon.

We have to conduct a test to determine whether or not the manufacturer's advertising campaign is legitimate.

<u><em>Let </em></u>\mu<u><em> = population average gasoline of new small cars in highway driving.</em></u>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq 50 miles per gallon   {means that the manufacturer's advertising campaign is not correct}

<u>Alternate Hypothesis</u>, H_A : \mu > 50 miles per gallon   {means that the manufacturer's advertising campaign is correct}

The test statistics that will be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                         T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where,  \bar X = sample average gasoline = 51.5 miles per gallon

              \sigma = population standard deviation = 6 miles per gallon

              n = sample of automobiles = 36

So, <em><u>test statistics</u></em>  =   \frac{51.5-50}{\frac{6}{\sqrt{36} } }

                               =  1.50

<em>Now at 0.05 significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is less than the critical values of z as 1.50 < 1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

<u>Also, P-value is given by the following formula;</u>

         P-value = P(Z > 1.50) = 1 - P(Z \leq 1.50)

                                            = 1 - 0.93319 = <u>0.067 or 6.7%</u>

Therefore, we conclude that the the manufacturer's advertising campaign is not correct as its new small cars average less than or equal to 50 miles per gallon in highway driving.

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3 years ago
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1st one on second row I think
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